Question

A water balloon is thrown at an angle of 30° with a velocity of 40 m/s. How long do you have to move out of the way if the balloon was 20m away from you when it was thrown?

Answer 1

Answer:

t=0.58s

Explanation:

We can consider only the horizontal component since the horizontal component of the velocity is constant ($v_x=vcos\theta$), and we want to know how much time it takes for the balloon to travel a horizontal distance $d_x$ at that speed. The definition of (horizontal) velocity is $v_x=\frac{d_x}{t}$, so we have:

$t=\frac{d_x}{v_x}=\frac{d_x}{vcos\theta}=\frac{(20m)}{(40m/s)cos(30^{\circ})}=0.58s$