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aleksandrvk [35]

3 years ago

11

A water balloon is thrown at an angle of 30° with a velocity of 40 m/s. How long do you have to move out of the way if the ballo

on was 20m away from you when it was thrown?

1 answer:

boyakko [2]3 years ago

6 0

Answer:

t=0.58s

Explanation:

We can consider only the horizontal component since the horizontal component of the velocity is constant ( $v_x=vcos\theta$ ), and we want to know how much time it takes for the balloon to travel a horizontal distance $d_x$ at that speed. The definition of (horizontal) velocity is $v_x=\frac{d_x}{t}$ , so we have:

$t=\frac{d_x}{v_x}=\frac{d_x}{vcos\theta}=\frac{(20m)}{(40m/s)cos(30^{\circ})}=0.58s$

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A charge feels a 7.89 x 10-7 N force when it moves 2090 m/s at a 29.4° angle to a 4.23 x 10-3 T magnetic field. What is the amou

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We have that the amount of the charge q is

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From the Question we are told that

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Generally, the equation for Force F is mathematically given by

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$q=1.8*10^{-7}$

In conclusion

The amount of the charge q is

$q=1.8*10^{-7}$

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