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3 years ago

explain how metamorphic rocks are formed, and explain the differences between regional and contact metamorphism?

1 answer:

5 0

Metamorphic rocks form when pre-existing or parent rocks (whether igneous, sedimentary, or even metamorphic) are altered by heat, pressure, and the chemical activity of fluids. When the dominant altering factor is heat, usually from direct contact , it may undergo fundamental change in texture and recrystallization is called contact metamorphism. While regional metamorphism, where rocks texture and minerals are changed by heat and pressure.

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A centrifuge is a device used to separate materials by their masses. A sample in a centrifuge is rotated at high speeds along a

german

Answer:

F = 1.047 10⁻² N

Explanation:

Let's use kinematics to find the angular acceleration

w = w₀ + α t

as for rest w₀ = 0

w = α t

α = w / t

let's reduce the magnitudes to the SI system

w = 1000 rev / min (2π rad/ 1 rev) (1 min/ 60s) = 104.72 rad / s

m = 1.00 g (1 kg / 1000 g) = 1,000 10⁻³ kg

r = 10.0 cm (1 m / 100 cm) = 0.100 m

let's calculate

α = 104.72 / 1

α = 104.72 rad / s²

angular and linear variables are related

a = α r

a = 104.72 0.100

a = 10.47 m / s²

finally we substitute in Newton's second law

F = 1 10⁻³ 10.47

F = 1.047 10⁻² N

8 0

3 years ago

When there is faster-moving water between two ships, are the ships sucked together or pushed together? explain?

Zigmanuir [339]

The ships should get suck together as the water must be replaced from the sides. Please mark Brainliest!!!

7 0

3 years ago

Velocity: You leave on a 549-mi trip in order to attend a meeting that will start 10.8 h after you begin your trip. Along the wa

rewona [7]

Answer:

1.55 h

Explanation:

Let the time to spend over dinner be t.

Since I need to spend 10.8 h for the whole trip, then I have 10.8 - t hours left to drive.

Speed = distance/time

$v = \dfrac{d}{10.8-t}$

$d = v(10.8-t)$

The distance is 549 and maximum speed is 65 mi/h.

$549 = 65(10.8 - t)$

$10.8-t = 8.45$

$t = 10.8 - 8.45 = 1.55 \text{ h}$

5 0

3 years ago

A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. Wha

Gwar [14]

A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. The change in the electric potential energy of the proton-field system when the proton travels to x = 2.50m is -3.40 × 10⁻¹⁶ J (Option B)

<h3 /><h3>How is the change in electric potential energy of the proton-field system calculated?</h3>

Work done on the proton =Negative of the change in the electric potential energy of the proton field
In the given case, W = -qΔV
-W = qΔV
= qEcosθ
Therefore, work done on the proton = -e(8.50× $10^2$ N/C)(2.5m)(1)
= -3.40× $10^-^1^6$ J
Any change in the potential energy indicates the work done by the proton.
Therefore the positive sign shows that the potential energy increases when the proton does the work.
The negative sign shows that the potential energy decreases when the proton does the work.