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Answer:
The correct answer to the question is (A)
When it hits the heavy rope, compared to the wave on the string, the wave that propagates along the rope has the same (A) frequency
Explanation:
The speed of a wave in a string is dependent on the square root of the tension ad inversely proportional to the square root of the linear density of the string. Generally, the speed of a wave through a spring is dependent on the elastic and inertia properties of the string

Therefore if the linear density of the heavy rope is four times that of light rope the velocity is halved and since
v = f×λ therefore v/2 = f×λ/2
Therefore the wavelength is halved, however the frequency remains the same as continuity requires the frequency of the incident pulse vibration to be transmitted to the denser medium for the wave to continue as the wave is due to vibrating particles from a source for example
Answer:
v =7.1 m/s
Explanation:
Given that
u = 3.35 m/s
t= 5 s
a= 0.75 m/s²
The final velocity = v
We know v = u +at
v=final velocity
u=initial velocity
Now by putting the values in the above equation
v = 3.35 + 0.75 x 5 m/s
v =7.1 m/s
Therefore the final velocity will be 7.1 m/s
Answer:
The solution is given in the picture attached below
Explanation:
The main difference is the source of the sediment that the rock is formed from. Clastic sedimentary rocks are formed mostly from silicate sediment derived by the breakdown of pre-existing rocks. Bioclastic rocks are formed by the accumulation of fragmented organic remains (such as shell-sand) - i.e. the sediment is of biological rather than non-biological origin.