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3 years ago

6

TRUE OR FALSE- Doing sports activities as your Cardio Training can be just as effective or more effective than running on a trea

dmill.
For 15 Points.

1 answer:

vivado [14]3 years ago

6 0

its true

dsdfsddsfsdfdsg

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A _______ property of gasoline is that it will _______ in air.

Misha Larkins [42]

A chemical property of gasoline is that it will burn in air. Gasoline is a substance that is used to power automobiles. Gasoline will oxidize in air which means that it reacts with oxygen in air. Hope this answers the question. Have a nice day.

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3 years ago

Read 2 more answers

An object of mass, m1 with a velocity, v1 collides with another object at rest (v2 = 0) with a mass, m2. After the collision, m1

goblinko [34]

Answer:

$v"_{1} = v_{1} tan$ Θ

$v^{"} _{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

Θ = $tan^{-1}(\frac{v^{"} _{1} }{v_{1} } )$

Explanation:

Applying the law of conservation of momentum, we have:

Δ $p_{x = 0}$

$p_{x} = p"_{x}$

$m_{1}v_{1} = m_{2}v"_{2} cos$ Θ (Equation 1)

Δ $p_{y} = 0$

$p_{y} = p"_{y}$

$0 = m_{1} v"_{1} - m_{2} v"_{2} sin$ Θ (Equation 2)

From Equation 1:

$v"_{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

From Equation 2:

$m_{2} v"_{2}$ sinΘ = $m_{1} v_{1}$

$v"_{1} = \frac{m_{2} v"_{2}sinΘ}{m_{1} }$

Replacing Equation 3 in Equation 4:

$v"_{1}=\frac{m_{2}\frac{m_{1}v_{1}}{m_{2}cosΘ}sinΘ}{m_{1}}$

$v"_{1}=v_{1}\frac{sinΘ}{cosΘ}$

$v"_{1}=v_{1}tan$ Θ (Equation 5)

And we found Θ from the Equation 5:

tanΘ= $\frac{v"_{1}}{v_{1}}$

Θ= $tan^{-1}(\frac{v"_{1}}{v_{1}})$

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3 years ago

You have a ball in your hand above the ground at rest which you then drop. What energy is involved in each part of this situatio

Juliette [100K]

When you hold the ball, you have potential energy, when you drop the ball, you have kinetic.

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3 years ago

A capacitor is charged to 8.0×10−4 C , then discharged by connecting a wire between the two plates. 35us after the discharge beg

Anettt [7]

Answer:

The average current is 19.567 A

Solution:

As per the question:

Charge, Q = $8.0\times 10^{- 4}\ C$

Time, t = $35\times 10^{- 6}\ s$

Now,

We know that current is constituted by the rate of transfer of the charge per unit time. Thus we can write:

I = $\frac{Q}{t}$ (1)

Now, the charge that was transferred is 86 % of the original value.

Therefore,

We replace Q by 0.86Q in eqn (1):

I = $\frac{0.86\times 8.0\times 10^{- 4}}{35\times 10^{- 6}} = 19.657\ A$

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3 years ago

Consider two metallic rods mounted on insulated supports. One is neutral, the other positively charged. You bring the two rods c

EastWind [94]

Answer:

I think it will be half of the initial charge

Explanation:

Because we know, the resulting charge will be q1+q2/2, since one is neutral so the charge will be half q/2

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3 years ago