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SOVA2 [1]
3 years ago
6

TRUE OR FALSE- Doing sports activities as your Cardio Training can be just as effective or more effective than running on a trea

dmill.
For 15 Points.
Physics
1 answer:
vivado [14]3 years ago
6 0

its true

dsdfsddsfsdfdsg

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In what section of the EM spectrum can we find visible light?
Bess [88]

Answer:

I think C. central region

Explanation:

6 0
2 years ago
Nichrome wire, often used for heating elements, has resistivity of 1.0 × 10-6 Ω ∙ m at room temperature. What length of No. 30 w
worty [1.4K]

Answer:

Length = 2.453 m

Explanation:

Given:

Resistivity of the wire (ρ) = 1 × 10⁻⁶ Ω-m

Diameter of the wire (d) = 0.250 mm = 0.250 × 10⁻³ m

Resistance of the wire (R) = 50 Ω

Length of the wire (L) = ?

The area of cross section is given as:

A=\frac{1}{4}\pi d^2\\\\A=\frac{1}{4}\times\ 3.14\times (0.250\times 10^{-3})^2\\\\A=0.785\times 6.25\times 10^{-8}\\\\A=4.906\times 10^{-8}\ m^2

We know that, for a constant temperature, the resistance of a wire is directly proportional to its length and inversely proportional to its area of cross section. The constant of proportionality is called the resistivity of the wire. Therefore,

R=\rho \frac{L}{A}

Expressing the above in terms of length 'L', we get:

L=\frac{RA}{\rho}

Plug in the given values and solve for 'L'. This gives,

L=\frac{50\times 4.906\times 10^{-8}}{1\times 10^{-6}}\ m\\\\L=\frac{2.453}{1}=2.453\ m

Therefore, length of No. 30 wire (of diameter 0.250 mm) is 2.453 m.

4 0
3 years ago
A ladybug sits 14 cm from the center of a turntable spinning at 33.33 rpm. The Sun is shining horizontally through the window an
kolbaska11 [484]

Answer:

The maximum velocity is 0.489 m/s

Explanation:

Maximum velocity (v) = angular velocity (w) × radius (r)

w = 33.33 rpm = 33.33×0.1047 = 3.4897 rad/s

r = 14 cm = 14/100 = 0.14 m

v = 3.4897×0.14 = 0.489 m/s

3 0
3 years ago
3. When two liquids are mixed and a solid
sashaice [31]

Answer:

D

Explanation:

6 0
2 years ago
A power source of 2.0 V is attached to the ends of a capacitor. The capacitance is 4.0 μF. What is the amount of charge stored i
ioda
C = 4 \ \mu F = 4 \cdot 10^{-6} \ F. \newline
q = Cu = 4 \cdot 10^{-6} \cdot 2 = 8 \cdot 10^{-6} = 0.000008 \ C.
8 0
3 years ago
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