Answer:The visible light contains 7 colours : Violet, indigo, Blue, Green, Yellow, Orange and Red.
White colour is formed by the interference of all 7 colours, thus white light has the combination of all frequencies of visible light.
Explanation:
The empirical formula is K₂O.
The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.
The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.
So, our job is to calculate the <em>molar ratio</em> of K to O.
Step 1. Calculate the <em>moles of each element
</em>
Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K
Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0
Step 2. Calculate the <em>molar ratio of each elemen</em>t
Divide each number by the smallest number of moles and round off to an integer
K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1
Step 3: Write the <em>empirical formula
</em>
EF = K₂O
Answer:
B. ribosome
Explanation:
In the ribosomes, the codons get paired with anti codons to create a polypeptide or protein.
A) NOPE!
B)Maybe
C)YUP this is the answer
D)meh...
Show the two (neutral) organic starting materials that would be used to synthesize the following ketone by a hydroxide mediated crossed‑aldol reaction the product formed is alpha-beta unsaturated carbonyl compound.
<h3>What is the Aldol-condensation ?</h3>
The condensation response among distinctive molecules of an aldehyde or ketone in a protic solvent which includes water or alcohol constitutes the crossed aldol response. When condensation is among distinctive carbonyl compounds, it's far referred to as crossed aldol condensation.
Applying the retrosynthetic evaluation technique, the systems of the beginning substances are decided via way of means of the usage of the bottom catalyzed for the crossed aldol mechanism. The beginning substances are aldehyde and ketone compounds that react with every different to present the goal molecule.
Read more about the aldehyde :
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