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Deffense [45]
3 years ago
9

Calculate the gravitational acceleration of a satellite that is in orbit at a distance of 1.0 x 10^8 meters from the center of t

he Earth (Mass of Earth is 6.0 × 10^24).
Physics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

g=0.035\ m/s^2

Explanation:

Given that,

Mass of Earth, m=6\times 10^{24}\ kg

We need to find the gravitational acceleration of a satellite that is in orbit at a distance of 10^8\ m from the center of the Earth.

Radius of earth is 6,371 km

The formula used to find the gravitational acceleration at a distance is given by :

g=\dfrac{Gm}{R^2}

R = r+d

g=\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}}{(10^8+6371\times 10^3)^2}\\\\g=0.035\ m/s^2

So, the gravitational acceleration is 0.035\ m/s^2.

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Answer:

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A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th
Evgen [1.6K]

Answer:

\dfrac{d\theta}{dt}=0.038\ rad/s

Explanation:

Given that

\dfrac{dx}{dt}= -1\ m/s

From the diagram

tan\theta=\dfrac{21}{x}

By differentiating with time t

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

When x= 10 m

tan\theta=\dfrac{21}{10}

θ = 64.53°

Now by putting the value in equation

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

sec^264.53^{\circ} \dfrac{d\theta}{dt}=-\dfrac{21}{10^2}\times (-1)

\dfrac{d\theta}{dt}=0.038\ rad/s

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8 0
3 years ago
If the truck has a mass of 2,000 kilograms , what's its momentum?(v=35 m/s)
katen-ka-za [31]

Answer:

\boxed {\boxed {\sf  70,000 \ kg*m/s}}

Explanation:

Momentum is the product of mass and velocity.

p=m*v

The mass of the truck is 2,000 kilograms and the velocity is 35 meters per second.

m= 2000 \ kg \\v= 35 \ m/s

Substitute the values into the formula and multiply.

p= 2000 \ kg * 35 \ m/s \\p= 70,000 \ kg*m/s

The truck's momentum is <u>70,000 kilograms meters per second.</u>

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A wildlife researcher is tracking a flock of geese. The geese fly 4.0 km due west, then turn toward the north by 40º and fly ano
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Wildlife researcher starts from a and then reaches b, he turns towards north 40 degree to move towards c.

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Total horizontal displacement = 4+4 cos40 =7.06 km

Total vertical displacement = 4 sin40 =2.57 km

Total displacement = \sqrt{7.06^2+2.57^2} = 7.51 km

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aliya0001 [1]
The answer is 5. To find the advantage you just divide 20 by 4.
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