A compound with the formula C6H12 is not considered a Saturated hydrocarbon.
Why is C6H12 isn't considered a Saturated hydrocarbon?
The ring's presence demonstrates that it is unsaturated. Keep in mind that the general formula for aliphatic hydrocarbons, CnH2n+2, serves as the foundation for its saturation. A chemical is unsaturated if it does not meet this requirement.
Example:
Hexane (C6H14)
C = 6; H = 14 = 2(6) + 2
resulting in hexane becoming saturated.
Cyclohexane(C6H12)
C = 6 and H = 12 do not equal 14 (x)!
cyclohexane is an unsaturated molecule as a result.
Cycloalkanes have the general formula C2H2n as well.
Hence, the given statement is false.
Learn more about the hydrocarbons here,
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# SPJ4
First, you should convert the temperature unit to absolute temperature.
Second, you shoul graph the points. Then you will find a pretty linear correlations among the points.
You can pick between using the best fit line or you could observe that as you get to higher temperatures the linear behavior is "more perfect".
I found this best fit line:
P = 2.608T + 14
Then, for T = 423K
P = 2.608(423) + 14 = 1117 mmHg
If you prefer to use the last two points, this is the calculus:
[P - P1] / [T - T1] = [P2 - P1] / [T2 - T1]
[P - 960]/[423 -373] = [960 - 880] / [373- 343]
=> P = 1093.3 mmHg.
You can pick any of the results 1177 mmHg or 1093 mmHg, You need more insight to choose one of them: conditions and error of the experiment for example.
3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.
Explanation:
data given:
H30+= 1.40 X 10^-4 M\
Henderson Hasslebalch equation to calculate pH=
pH = -log10(H30+)
putting the values in the equation:
pH = -log 10(1.40 X 10^-4 M)
pH = 3.85
pH + pOH =14
pOH = 14 - 3.85
pOH = 10.15
The OH- concentration from the pOH by the equation:
pOH = -log10[OH-]
10.5= -log10[OH-]
[OH-] = 10^-10.5
[OH-] = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.
That would be <span>Johannes Gutenberg a German inventor from the 1400's </span>
Answer:
Is it prescribe to you?If so than yes if not then no need to
Explanation:
