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Initial [ HCO2H] = moles * volume
=0.35 moles * 1 L = 0.35 M
by using ICE table:
HCO2H ↔ H+ + HCO2-
initial 0.35 M 0 0
change - X +X +X
Equ (0.35 - X) X X
∴ Ka = [H+][HCO2-] / [HCO2H]
by substitution:
1.8 x 10^-4 = X^2 / (0.35-X) by solving for X
∴ X = 0.0079 or 7.9 x 10^-3
∴ [H+] = X = 7.9 x 10^-3 M
Oleic acid belongs to class of alkene and in alkenes, addition of
across
that is carbon carbon double bond results in the formation of alkane as a product in the presence of specific catalyst such as nickel, palladium and platinum. The reaction is said to be hydrogenation reaction.
Oleic acid (
) consist of 17 carbon atoms attached to 33 hydrogen atoms with one double bond between two carbon atoms and one carboxylic group i.e.(
). When oleic acid is hydrogenated or reacts with hydrogen in the presence of catalyst, then the carbon carbon double breaks by the addition
and alkane product i.e. stearic acid (
) is formed.
The chemical reaction is shown in the image.
Answer:
The answer is
<h2>4.0 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
<h3>

</h3>
From the question
mass of block = 36 g
volume = 9 cm³
The density is

We have the final answer as
4.0 g/cm³
Hope this helps you
Answer: 9.53 *2= 19.06
Explanation:
The law of multiple proportions states that if two elements combines to form more than one compound the ratio of masses of the second element which combines to the fixed mass of the first element will always be the ratios of the small whole numbers.
in case of carbon monoxide, mass of carbon will be the same of mass of oxygen.
But in case of carbon dioxide, if carbon is 9.53 units then oxygen will be twice as that of carbon.
CO2, so 9.53*2= 19.06 grams of oxygen will combine with 9.53 grams of carbon to form carbon dioxide.