Answer:
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Answer:
Parte B : 31.18º , Parte C: 31.17º
Explanation:
Parte B: The angle between the glass and the water before it enters the water is going to be equal to the value of the angle when it enters the glass , 27.13º.
Using the formula n1 senθ1 = n2 senθ2 , where n1=1.51 , θ1=27.13º, n2=1.33 , it gives us θ2=31.18º.
Parte C: n1= 1 , θ1=43.5º, n2=1.33
Using the same formula : n1 senθ1 = n2 senθ2 , it gives us θ2= 31.17º.
Answer:
A: They produce a real image.
Explanation:
The images formed on the retina of the eye for a normal visibility must always be real.
Only a real image can be physically projected on any physical object whereas the virtual images are visible due to reflections.
- The nearsightedness is corrected with the help of a concave lens since it is the condition of the eye lens remaining thick and curved to converge the rays entering the eyes after a shorter distance which results in their image formation even before the retinal surface so to initially diverge them a bit so that they converge on the retinal surface and form the image there we use concave lens. Vice-versa of the above justification in the case of farsightedness.
Answer:
The question implies that force of friction is 2.1E4 N
F = M v^2 / R frictional force needed to supply this centripetal force
2.1E4 = M v^2 / R
v^2 = R * 2.1E4 / M
v^2 = 120 * 2.1E4 / 2.5E3 = 1200 * 2.1 / 2.5 = 1008 m^2/s^2
v = 31.7 m/s max speed of truck (about 70 MPH)
Answer:
Explanation:
We are given that
Gauge pressure at 3.4 degree Celsius,P=
We have to find the gauge pressure in tire when the temperature rises to 26 degree Celsius.
Atmospheric pressure=
K=273+Degree Celsius
Gauge pressure in tire when the temperature rises to 26 degree Celsius.=