Answer:
yes, 800 has 1 significant digit
neither leading zero nor trelling zero are significant figure except when there's a decimal point
Answer:
2991.47 [cm^2]
Explanation:
To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:
![3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}]](https://tex.z-dn.net/?f=3.22%5Bft%5E%7B2%7D%5D%2A%5Cfrac%7B12%5E%7B2%7Din%5E%7B2%7D%20%7D%7B1%5E%7B2%7Dft%5E%7B2%7D%7D%20%2A%5Cfrac%7B2.54%5E%7B2%7Dcm%5E%7B2%7D%20%20%7D%7B1%5E%7B2%7Din%5E%7B2%7D%20%7D%20%5C%5C2991.47%5Bcm%5E%7B2%7D%5D)
I think its b because when there is unbalanced forces it accelerates.
Hope this helps you out
Answer:
1.06 m
Explanation:
Since the charge is at the centre of two concentric spheres, we use the formula for electric potential due to a point charge. V = kq/r. Let r₁ be the radius of the sphere with potential, V₁ = 200 V and r₂ be the radius of the sphere with potential, V₂ = 82.0 V. From V = kq/r, r = kq/V. So that r₁ = kq/V₁ and r₂ = kq/V₂. The magnitude of the difference r₁ - r₂ is the distance between the two surfaces. q the charge equals 1.63 × 10⁻⁸ C
r₂ - r₁ = kq/V₂ - kq/V₁ = kq(1/V₂ - 1/V₁) = 1.63 × 10⁻⁸ × 9 × 10⁹ (1/82 -1/200) m = 1.63 × 10⁻⁸ × 9 × 10⁹ (0.0122 - 0.005) = 1.63 × 10⁻⁸ × 9 × 10⁹(0.0072) m = 1.06 m
The distance between them is 1.06 m
