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Afina-wow [57]
3 years ago
12

Classify the following substances as a Bronsted-Lowry acid, Bronsted-Lowry base, Lewis acid, and/or Lewis base.A. HCl, BF_3,B. C

Cl_3, -HC. CH_2O, CH_3ClD. -OCH_3 , NH_3
Chemistry
1 answer:
ZanzabumX [31]3 years ago
6 0

Answer:

A. HCl -> Bronsted-Lowry acid, BF3 -> Lewis acid

B. CCl3 -> Lewis acid, -HC -> Lewis acid or Bronsted-Lowry acid

C. H2O -> Bronsted-Lowry acid or Bronsted-Lowry base, CH3Cl -> Lewis base

D.-OCH3 -> Lewis base, NH3 -> Bronsted-Lowry acid or Lewis base.

Explanation:

For the Bronsted-Lowry theory, acids are the substances that can donate a proton H+ and bases are the substances that can receive a pronto H+.

For the Lewis theory, acid is the substance that can gain a pair of electrons, and the base is the substances that can donate the pair of electrons.

A. HCl -> The substance has a proton (H+) and it can donate it, so it's a Bronsted-Lowry acid. BF3 -> The boron (B), still has space in its shells to receive a pair of electrons, so it's a Lewis acid.

B. CCl3 -> The carbon didn't make all the bonds it can do (4), so it still can receive electrons, thus it's a Lewis acid. -HC-> It can lose the proton (H+) as a Bronsted-Lowry acid, os gains a pair of electrons at the carbon, as a Lewis acid.

C. H2O -> It can gain a proton and forms the ion H3O+, or it can lose a proton and form the ion OH-, so it can be a Brosted-Lowy acid or a Bronsted-Lowry base. CH3Cl -> It can donate pair of electrons (the hydrogen is to attached to the carbon, so it will not be lost), so it works as a Lewis base.

D. -OCH3 -> The oxygen still has pairs of electrons, which it can donate, so it's a Lewis base. NH3 -> It can gain a proton and forms the ion NH4+, so it'll be a Bronsted-Lowry acid, but the nitrogen still has electrons, which it can donate, working as a Lewis base.

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weqwewe [10]

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Answer is 74.42 if you are on cK-12.

Explanation:

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3 years ago
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How many grams of calcium will react with 10.0 grams of nitrogen according to the
riadik2000 [5.3K]

Answer:

The answer to your question is 42.9 g of Ca

Explanation:

Data

mass of Ca = ?

mass of N₂ = 10 g

Balanced  chemical reaction

                 3Ca  +  N₂  ⇒   Ca₃N₂

Process

1.- Calculate the molar mass of the reactants.

Ca = 3(40) = 120 g

N₂ = 2(14) = 28 g

2.- Calculate the mass of Calcium using proportions and the molar mass of the reactants.

                    120 g of Ca ---------------- 28 g of N₂

                       x               ---------------- 10 g of N₂

                               x = (10 x 120) / 28

                               x = 1200 / 28

                               x = 42.9 g of Ca

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3 years ago
How is cloning different from hybridization?
kvasek [131]

1. Hybridization is a method of sexual reproduction whereas cloning is a method of asexual reproduction.

2. Hybrid animals are sterile, but cloned animals are fertile.

3. Hybrid organisms contain DNA from both male and female parents but cloned organisms contain DNA from only one type of parent.

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9. A graduated cylinder is filled with water to a level of 40.0 mL. When a piece of copper is lowered into the cylinder, the wat
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Answer:

Mass = 208.26 g

Explanation:

Given data:

Volume of water = 40.0 mL

Volume of water + copper = 63.4 mL

Volume of copper = ?

Density of copper = 8.9 g/cm³

Mass of copper = ?

Solution:

Volume of copper:

Volume of copper = (Volume of water + copper ) - Volume of water

Volume of copper =  63.4 mL -  40.0 mL

Volume of copper = 23.4 mL

Mass of copper:

density = mass/volume

8.9 g/cm³ = mass/23.4 mL

 cm³ = mL

Mass = 8.9 g/mL × 23.4 mL

Mass = 208.26 g

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3 years ago
A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s
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Answer:

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Explanation:

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This problem involves a weak diprotic acid which we can solve by realizing they amount  to buffer solutions.  In the first  deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

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it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

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For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

           

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