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jekas [21]
3 years ago
13

Calculate the acceleration of the object from 3 seconds to 7 seconds (1pt). Show your work (1pt) and make sure to include the co

rrect units (1pt)! Speed at 3 seconds - 0 m/s Speed at 7 seconds - 8 m/s

Physics
2 answers:
NARA [144]3 years ago
7 0

Answer: 2m/s^2

Explanation: a=v-u/t2-t1

V=8m/s

U=0m/s

T1=3s

T2=7s

a=8-0/7-3

a=8/4

a= 2m/s^2

Juliette [100K]3 years ago
5 0

Explanation:

Below is an attachment containing the solution.

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8. When you see a stopped local bus (1 point)
elena55 [62]

Answer: be alert for pedestrians near the bus.

Explanation: Due to road accidents many Governments around the world has adopted and put in place certain rules and regulations with regards to road safety, this is so to prevent the or reduce the chances of accidents happening.

Road safety rules are rules and guidelines put in place by Government in order to prevent road accidents and maintain a free flow of traffic. An example of such rules is 'be alert for pedestrians near the bus ' when approaching a local bus that is stopped.

5 0
3 years ago
The efficiency of a device such as a lamp can be calculated using this equation:
loris [4]

efficiency = (useful energy transferred ÷ energy supplied) × 100

It's easy to use this formula, but we have to know both the useful energy and the energy supplied.  The drawing doesn't tell us the useful energy, so we have to find a clever way to figure it out.  I see two ways to do it:

<u>Way #1:</u>

We all know about the law of conservation of energy.  So we know that the total energy coming out must be  250J, because that's how much energy is going in.  The wasted energy is 75J, so the rest of the 250J must be the useful energy . . . (250J - 75J) = 175J useful energy.

(useful energy) / (energy supplied) =  (175J) / (250J) = <em>70% efficiency</em>

================================

<u>Way #2: </u>

How much of the energy is wasted ? . . . 75J wasted

What percentage of the Input is that 75J ? . . . 75/250 = 30% wasted

30% of the input energy is wasted.  That leaves the other <em>70%</em> to be useful energy.

6 0
3 years ago
Read 2 more answers
I need help with these questions.
strojnjashka [21]

I'll go ahead and answer the ones here without an answer. For reference, the half-life formula is <em>final amount = original amount(1/2)^(time/half-life)</em>

<em />

4) 12.5g

x = 100(1/2)^(63/21)

5) 50g

3.125 = x(1/2)^(0.1/0.025)

6) 500g

x = 4000(1/2)^(525/175)

7) 0.24g

0.06 = x(1/2)^(11430/5730)

8) 125g

x = 1000(1/2)^(17100/5700)

Hope this helps! :)

4 0
3 years ago
A bicycle racer is going downhill at 11.0 m/s when, to his horror, one of his 2.25 kg wheels comes off when he is 75.0 m above t
alex41 [277]

Answer:

a.) Speed V = 29.3 m/s

b.) K.E = 1931.6 J

Explanation: Please find the attached files for the solution

4 0
3 years ago
A rhinoceros is at the origin of coordinates at time t1 = 0. for the time interval from t1 = 0 to t2 = 21.5 s, the rhino's avera
Ainat [17]
A) The rhino's average velocity on the x-axis is v_x=-3.8 m/s. The position x after time t=21.5 s can be found by using the relationship:
x=x_0 + v_x t=0+(-3.8 m/s)(21.5 s)=-81.7 m
where we used x_0=0 as the x-position at time t=0, since the rhino was at the origin.

SImilarly, the average velocity on the y-axis is v_y=+4.5 m/s, and the y-position after time t=21.5 s can be found by using:
y=y_0+(+4.5 m/s)(21.5 s)=+96.8 m
where we used y_0=0 since the the rhino was at the origin at time t=0.

b) The distance of the rhino from the origin can be calculated by calculating the resultant of the displacement of the rhino on both axes:
d= \sqrt{x^2+y^2}= \sqrt{(-81.7 m)^2+(96.8m)^2}=126.7 m
6 0
3 years ago
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