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jekas [21]
3 years ago
13

Calculate the acceleration of the object from 3 seconds to 7 seconds (1pt). Show your work (1pt) and make sure to include the co

rrect units (1pt)! Speed at 3 seconds - 0 m/s Speed at 7 seconds - 8 m/s

Physics
2 answers:
NARA [144]3 years ago
7 0

Answer: 2m/s^2

Explanation: a=v-u/t2-t1

V=8m/s

U=0m/s

T1=3s

T2=7s

a=8-0/7-3

a=8/4

a= 2m/s^2

Juliette [100K]3 years ago
5 0

Explanation:

Below is an attachment containing the solution.

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Determine the binding energy per nucleon of an mg-24 nucleus. the mg-24 nucleus has a mass of 24.30506. a proton has a mass of 1
My name is Ann [436]

The mass of Mg-24 is 24.30506 amu, it contains 12 protons and 12 neutrons.

Theoretical mass of Mg-24:

The theoretical mass of Mg-24 is:

Hydrogen atom mass = 12 × 1.00728 amu = 12.0874 amu

Neutron mass = 12 x 1.008665 amu = 12.104 amu

Theoretical mass = Hydrogen atom mass + Neutron mass = 24.1913 amu

Note that the mass defect is:

Mass defect = Actual mass - Theoretical mass : 24.30506 amu- 24.1913 amu= 0.11376 amu

Calculating the binding energy per nucleon:

\frac{B.E.}{nucleon}=\frac{(0.11376amu)(931Mev/amu}{24nucleons}  = 4.41294 Mev/nucleon

So approximately 4.41294 Mev/necleon


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3 years ago
A 500g object falls off a cliff and losers 100 J from its gravitational potential energy store. if the gravitational field stren
ludmilkaskok [199]

Answer : Height, h = 20.4 m

Explanation :

It is given that,

Mass of an object, m = 500 g = 0.5 kg

Gravitational potential energy, PE = 100 J

The Gravitational potential energy is the energy which is possessed due to the height and gravity of an object. It is given as :

PE = m g h

where,

h is the height of the cliff.

100\ J=0.5\ kg\times 9.8\ m/s^2\times h

h = 20.40 m

So, the height of the cliff is 20.4 m.

7 0
3 years ago
An empty parallel plate capacitor is connected between the terminals of a 4.4-V battery and charged up. The capacitor is then di
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Answer:

d

Explanation:

idk

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Dish-shaped reflectors are used to steer microwaves in order to establish communications links between nearby buildings. Those r
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A "screen" or even just a set of parallel bars are highly reflective to electromagnetic waves as long as the open spaces are small compared to the wavelengths.

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(I even worked on a microwave system in South America where huge grid dishes were used on a 90-mile link.)

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