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Sauron [17]
3 years ago
8

Equation for the reaction of rubidium with an Arrhenius base

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
5 0

Answer:

No reaction.

Explanation:

An Arrhenius base (like NaOH) increases the concentration of hydroxide ions present in the solution.

If you add Rb to an aqueous solution of NaOH, you will get an explosion.

However, the Rb does not react with the OH^-. Instead, it reacts rapidly with the water.

2Rb + 2H2O → 2RbOH + H2

So much heat is generated that the hydrogen explodes:

2H2 + O2 → 2H2O

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Answer:

pH = 9.48

Explanation:

We have first to realize that NH₃ is a weak base:

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and we are adding this weak base to a solution of NH₄NO₃ which being a salt dissociates 100 % in water.

Effectively what we have here is a buffer of a weak base and its conjugate acid. Therefore, we need the Henderson-Hasselbach formula for weak bases given by:

pOH = pKb + log ( [ conjugate acid ] / [  weak base ]

mol NH₃ = 0.139 L x 0.39 M = 0.054 mol

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Now we have all the information required to calculate the pOH ( Note that we dont have to calculate the concentrations since in the formula they are a ratio and the volume will cancel out)

pOH = -log(1.8 x 10⁻⁵) + log ( 0.032/0.054) = 4.52

pOH + pH = 14 ⇒ pH = 14 - 4.52 = 9.48

The solution is basic which agrees  with NH₃ being  a weak base.

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Explanation:

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Explanation:

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