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VLD [36.1K]
3 years ago
7

Calculate the average atomic mass of sulfur if 95.00% of all sulfur atoms have a mass of 31.972 amu, 0.76% has a mass of 32.971

amu and 4.22% have a mass of 33.967 amu.​
Chemistry
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

32.057 amu

Explanation:

\text{Average atomic mass = Mass}\times \text{abundances}

M=95\%\ \text{of}\ 31.972 +0.76\%\ \text{of}\ 32.971 +4.22\%\ \text{of}\ 33.967 \\\\M=\dfrac{95}{100}\times  31.972 +\dfrac{0.76}{100}\ \times \ 32.971 +\dfrac{4.22}{100} \times \ 33.967\\\\M=32.057\ \text{amu}

So, the average atomic mass of sulfur is 32.057 amu.

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5 0
2 years ago
What is the speed of the silver sphere at the moment it hits the ground? (Assume that energy is conserved during the fall and th
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Complete question:

Consider the two spheres shown here, one made of silver and the other of aluminum. The spheres are dropped from a height of 2.1 m. (composition of sphere : density is 10.49 g/cm³, volume is 196 cm³), (composition of aluminum : density is 2.7 g/cm³, volume is 196 cm³).

What is the speed of the silver sphere at the moment it hits the ground? (Assume that energy is conserved during the fall and that 100% of the sphere’s initial potential energy is converted to kinetic energy by the time impact occurs.)

Answer:

The speed of the silver sphere at the moment it hits the ground is 6.416 m/s

Explanation:

Potential energy of the silver sphere = mgh

where;

g is acceleration due to gravity = 9.8 m/s²

h is height above the ground = 2.1m

m is mass of the silver sphere =?

Density = mass/volume

mass of the silver sphere = density X volume = (10.49 g/cm³) X (196cm³ )

mass of the silver sphere = 2056.04 g = 2.056 kg

Potential energy of the silver sphere =  (2.056 X 9.8 X 2.1) J

Potential energy of the silver sphere = 42.31248 J

If energy is conserved and 100% potential energy is converted to kinetic energy, the speed of the silver sphere will be calculated as follows:

Kinetic Energy (K.E) = 1/2mv²

where;

m is mass of the sphere in kg = 2.056kg

v is the velocity of the silver sphere = ?

If energy is conserved; Potential energy = Kinetic energy

42.31248 = 1/2mv²

v² = (42.31248 X 2)/m

v² = (42.31248 X 2)/2.056

v² = 41.16

v = √41.16

v = 6.416 m/s

Therefore, the speed of the silver sphere at the moment it hits the ground is 6.416 m/s

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