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LenKa [72]
3 years ago
10

A constant magnetic field passes through a single rectangular loop whose dimensions are 0.35m x 0.55m. The magnetic field has a

magnitude of 2.1T and is inclined at an angle of 65 degrees with respect to the normal to the plane of the loops. (a) If the magnetic field decreases to zero in a time of 0.45s, what is the magnitude of the average emf induced in the loop.(b) If the magnetic field remains constant at its initail calue of 2.1T, what is the magnitude of the rate ΔA/Δt at which the area should change so that the average emf has the same magnitude as in part (a)?

Physics
1 answer:
Cloud [144]3 years ago
4 0

Answer:

E = 0.38V

Explanation:

See attachment below.

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When a 2.50 kg object is hung vertically on a certain light spring described by hookes law the spring stretches 2.76 cm.
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F=K*X,
F=M*a 

M*a=K*X

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4 years ago
A circular window of 30 cm diameter in a submarine can withstand a maximum force of 5.20 × 105 N. The maximum depth in a lake to
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Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

         F = 5.20 \times 10^{5} N

         g = 9.8 m/s

         radius = \frac{diameter}{2}

                    = \frac{30 cm}{2} = 15 cm = 0.15 m   (as 1 m = 100 cm)

Formula to calculate depth is as follows.

        F = \rho \times g \times h \times A

or,      h = \frac{F}{\rho \times g \times A}        

       h = \frac{5.2 \times 10^{5}}{1000 \times 9.8 \times (3.1416 \times (0.15 m^{2})}

           = 751 m

Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.

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Answer:

A.

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Explanation:

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