Answer:
346.01 × 10² Lux
Explanation:
Given:
luminance of the sun at zenith at sea level, Ls = 1600 × 10 cd/m²
The diameter of the sun's photosphere = 8.64 × 10 miles = 45.62 × 10⁸ ft
or
Radius, r =
or
r = 22.81 × 10⁸ ft
The distance from the sun to the earth = 92.9 × 10 miles = 49.05 x 10¹⁰ ft
Now,
Lumen = Luminance × 4πr²
or
Lumen = 1600 × 10 cd/m² × 4πr² .....................(1)
also,
Illumination =
on substituting lumen from 1
Illumination =
or
Illumination =
or
Illumination = 346.01 × 10² Lux
How do you mean? I mean, physic professors teach physics...
Answer:
35 Joules
Explanation:
Applying
Input Energy(Q) = Useful energy output(U)+Wasted Energy(W)
Q = U+W.............................. Equation 1
Make U the subject of the equation
U = Q-W................... Equation 2
From the question,
Given: Q = 120 Joules, W = 85 Joules
Substitute these values into equation 2
U = 120-85
U = 35 Joules
Answer:
<h2>In physics and chemistry, ionization energy or ionisation energy is the minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom or molecule. It is quantitatively expressed as </h2><h2>X(g) + energy ⟶ X+(g) + e−</h2>
<h3>Hope it helps you Sharon (Rawrr) </h3>