The answer is Fuse. Circuit breakers and fuses are generally known as "Overload Protection Devices. The difference between a fuse and a circuit breaker is that a fuse is a one time circuit element while a circuit breaker is a multiple use device. If you were designing a circuit for a reading lamp, a fuse would do. Since almost all household installed a circuit breaker for outlets, etc,
Answer:
10.89 J.
Explanation:
The following data were obtained from the question:
Mass (m) = 12.5 kg
Velocity (v) = 1.32 m/s
Work done =?
To obtain the workdone, we shall determine the kinetic energy of the object since work and energy has the same unit of measurement. This is illustrated below:
Mass (m) = 12.5 kg
Velocity (v) = 1.32 m/s
Kinetic energy (K.E) =?
K.E = ½mv²
K.E = ½ × 12.5 × 1.32²
K.E = 6.25 × 1.7424
K.E = 10.89 J
The kinetic energy of the object is 10.89 J. Hence, the workdone in bringing the object to rest is 10.89 J.
To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

Here,
m = Order of the fringes
D = Distance between slits
= Wavelength
Replacing with our values we have,


Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then



Thus the width of the central maximum is


Therefore the widht is 0.466m
too much static electricity can cause a negative reaction such as the balloons repelling away from one another.
Answer:
V = E * d
E = (200 J/C) / .024 m = 8330 J / C-m
1/2 m v^2 = V q potential energy of electron
v^2 = 2 * 200 J/C * 1.6E-19 C / 9.11 E-31 kg
v^2 = 400 * 1.6E-19 / 9.11 E-31 N-m / kg
v = 8.4E6 m/s