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natta225 [31]
3 years ago
13

An object moving with a speed of 35M/s and has a kinetic energy of 1500 J what is the mass of the object

Physics
1 answer:
Lelu [443]3 years ago
7 0

2.45 Kg

Explanation:

K.E = 0.5 mv^2

1500 = 0.5 × m × (35)^2

1500= m × 0.5 × 1225

1500 = m × 612.5

1500/612.5 = m

2.45 = m

m = 2.45kg

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How much heat would be needed to completely evaporate 31.5 g of boiling water at a temperature of 100 "C? Express your answer in
BaLLatris [955]

Answer:

Heat needed = 71.19 J

Explanation:

Here heat required can be calculated by the formula

            H = mL

M is the mass of water and L is the latent heat of vaporization.

Mass of water, m = 31.5 g = 0.0315 kg

Latent heat of vaporization of water = 2260 kJ/kg

Substituting

            H = mL = 0.0315 x 2260 = 71.19 kJ

Heat needed = 71.19 J

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Two objects have charges 2.0 C and 1.0 C. If the objects are placed 2 meters apart, what is the magnitude of the force that the
kondor19780726 [428]

Answer:

4.5\cdot 10^9 N

Explanation:

The electric force between two charged objects is given by:

F=k\frac{q_1 q_2}{r^2}

where:

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q1 and q2 are the charges of the two objects

r is their separation

In this problem:

q1 = 2.0 C

q2 = 1.0 C

r = 2 m

So, the electric force is

F=(9\cdot 10^9 Nm^2C^{-2})\frac{(2.0 C)(1.0 C)}{(2 m)^2}=4.5\cdot 10^9 N

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How much brighter is a Sun-like star than the reflected light from a planet orbiting around it?
zloy xaker [14]

Answer:

E) a billion times brighter

Explanation:

  • <u>The sun is a star, which is about billion times brighter as the reflected light from any planet orbiting around it. </u>
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3 years ago
A horizontal force of 40N is needed to pull a 60kg box across the horizontal floor at which coefficient of friction between floo
Mazyrski [523]

Answer:

Coefficient of friction is 0.068.

Work done is 320~J.

Explanation:

Given:

Mass of the box (m): 60 kg

Force needed (F): 40 N

The formula to calculate the coefficient of friction between the floor and the box is given by

F=\mu mg...................(1)

Here, \mu is the coefficient of friction and g is the acceleration due to gravity.

Substitute 40 N for F, 60 kg for m and 9.80 m/s² for g into equation (1) and solve to calculate the value of the coefficient of friction.

40 N=\mu\times60 kg\times9.80 m/s^{2} \\~~~~~\mu=\frac{40 N}{60 kg\times9.80 m/s^{2}}\\~~~~~~~=0.068

The formula to calculate the work done in overcoming the friction is given by

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Substitute  40 N for F and 8 m for d into equation (2) to calculate the work done.

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3 years ago
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