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abruzzese [7]
4 years ago
5

What’s the force of a pitching machine on a baseball?

Physics
2 answers:
balandron [24]4 years ago
7 0

Answer:

Force, F = 9 N

Explanation:

Initial velocity of the baseball, u = 0 m/s

Final velocity of the baseball, v = 30 m/s

Time taken, t = 0.5 s

Mass of the baseball, m = 0.15 kg

We know that the force of a pitching machine on a baseball is given by using second law of motion. It is given by :

F=ma

F=m\times \dfrac{v-u}{t}

F=0.15\times \dfrac{30}{0.5}

F = 9 N

So, the force of 9 N is pitching machine exert on a baseball. Hence, this is the required solution.

____ [38]4 years ago
6 0

Answer:

F = 9 N

Explanation:

As we know that the acceleration of ball is given as rate of change in velocity of the object

so here we will have

a = \frac{dv}{dt}

here we know that

v_i = 0

v_f = 30 m/s

\Delta t = 0.5 s

now we will have

a = \frac{30 - 0}{0.5} = 60 m/s^2

now in order to find the force we will use Newton's II law which is given as

F = ma

now by above formula we have

F = (0.15)(60) = 9 N

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P = m*v

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Peso = m*9.8m/s^2 = 175N

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Vx = 36m/s

Mientras que para la velocidad vertical, usamos la conservación de la energía:

E = U + K

Apenas se suelta la caja, esta tiene velocidad cero, entonces su energía cinética será cero y la caja solo tendrá energía potencial (Si bien la caja tiene velocidad horizontal en este punto, por la superposición lineal podemos separar el problema en un caso horizontal y en un caso vertical, y en el caso vertical no hay velocidad inicial)

Entonces al principio solo hay energía potencial:

U = m*g*h

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m = masa

g = aceleración gravitatoria

h = altura  

Sabemos que la altura inicial es 60m, entonces la energía potencial es:

U = 175N*60m = 10,500 N

Cuando la paca esta próxima a golpear el suelo, la altura h tiende a cero, por lo que la energía potencial se hace cero, y en este punto solo tendremos energía cinética, entonces:

10,500N = (m/2)*v^2

De acá podemos despejar la velocidad vertical justo antes de golpear el suelo.

√(10,500N*(2/ 17.9 kg)) = 34.25 m/s

La velocidad vertical es 34.25 m/s

Entonces el vector velocidad se podrá escribir como:

V = (36 m/s, -34.25 m/s)

Donde el signo menos en la velocidad vertical es porque la velocidad vertical es hacia abajo.

Reemplazando esto en la ecuación del momento obtenemos:

P = 17.9kg*(36 m/s, -34.25 m/s)  

P = (644.4 N, -613.075 N)

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