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ivanzaharov [21]
3 years ago
12

What happens in a buffer when the level of H+ ions in solution increases?

Chemistry
2 answers:
hram777 [196]3 years ago
6 0

Answer:it accepts H+

Explanation:

erastova [34]3 years ago
5 0

There are two kinds of buffer

a) acidic buffer

b) basic buffer

They both resist change in pH on addition of small amount of strong acid or base

as asked in question we will consider addition strong acid that is [H+]

a) acidic buffer: it is a mixture of weak acid and its salt with strong base

say CH3COOH  + CH3COO-Na+

When we add H+, the H+ are being consumed by acetate ions to give acetic acid

CH3COO-  + H+  ---> CH3COOH

So it accepts H+

b)basic buffer

Example: NH4OH  + NH4Cl

when we add H+ , the OH- will react with it to form water

So it accepts H+

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anyanavicka [17]

Answer:

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6 0
3 years ago
Convert 4.5 X 1022 molecules of H2O to moles.
noname [10]

Answer:

<h3>The answer is 0.075 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{4.5 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.074750830...

We have the final answer as

<h3>0.075 moles</h3>

Hope this helps you

3 0
3 years ago
Consider the following equilibrium: 4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g) Which of the following is a correct equilibrium expressio
jeka57 [31]
To be able to write correctly the equilibrium expression of a reaction, we need to know the balanced reaction and the phases of the substances in the reaction. When substances are solid, pure liquid they are not included in the expression. We do as follows:

<span>4KO2(s) + 2H2O(g) = 4KOH(s) + 3O2(g)

K = [O2]^3 / [H2O]^2</span>
5 0
3 years ago
24 grams of CH4 was added to the above reaction. Calculate the theoretical yield of CO2. A. 66 grams B. 33 grams c. 132 grams. D
Sonbull [250]

Answer:

Option A. 66 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CH₄ + 2O₂ —> CO₂ + 2H₂O

Next, we shall determine the mass of CH₄ that reacted and the mass of CO₂ produced from the balanced equation. This is illustrated below:

Molar mass of CH₄ = 12 + (4×1)

= 12 + 4 = 16 g/mol

Mass of CH₄ from the balanced equation = 1 × 16 = 16 g

Molar mass of CO₂ = 12 + (16×2)

= 12 + 32 = 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

16 g of CH₄ reacted to produce 44 g of CO₂.

Finally, we shall determine the theoretical yield of CO₂. this can be obtained as follow:

From the balanced equation above,

16 g of CH₄ reacted to produce 44 g of CO₂.

Therefore, 24 g of CH₄ will react to produce = (24 × 44) /16 = 66 g of CO₂.

Thus, the theoretical yield of CO₂ 66 g

8 0
3 years ago
Not sure what to do can you help
NeTakaya

sorry i don't know the answer i'm really sorry

7 0
3 years ago
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