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3 years ago

How much to the left of the lens is the object?

Physics

1 answer:

stich3 [128]3 years ago

4 0

An object is 16.0 cm to the left of a thins lens. The lens forms an image 36.0 cm to the right of the lens.

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Can somebody help me with this I need to pass

son4ous [18]

<h2>Answer:Radiation-3,Conduction-1,Convection-2</h2>

Explanation:

Radiation is the transfer of heat through electromagnetic waves.

These waves do not require any medium.This is the way we get heat from sun.Radiation is the quickest mode to transfer of heat.

Conduction is the transfer of heat through collisions of atomic particles.

This phenomenon largely occurs in solids like metals.The neighbour atoms sets the atoms into random motion thereby raising the temperature.

Convection is the transfer of heat through actual movement of medium particle.

This phenomenon occurs in gases an liquids.The medium particles actually traverse through the space transferring the heat.

5 0

3 years ago

A fan at a rock concert is 50.0 m from the stage, and at this point the sound intensity level is 114 dB. Sound is detected when

Marianna [84]

Answer:

A) $P=13.92\ J.s^{-1}$

B) $v=3730.9912\ m.s^{-1}$

C) $v=74.44\ mm.s^{-1}$

D) mosquitoes speed in part B is very much larger than that of part C.

Explanation:

Given:

Distance form the sound source, $s=50\ m$

sound intensity level at the given location, $\beta=114\ dB$

diameter of the eardrum membrane in humans, $d=8.4 \times 10^{-3}\ m$

We have the minimum detectable intensity to the human ears, $I_0=10^{-12}\ W.m^{-2}$

(A)

<u>Now the intensity of the sound at the given location is related mathematically as:</u>

$\beta=10\ log(\frac{I}{I_0} )$ ..........................................(1)

$114=10\ log\ (\frac{I}{10^{-12}} )$

$11.4=log\ I+12\ log\ 10$

$I=0.2512\ W.m^{-2}$

$I=\frac{P}{A}$

$0.2512=\frac{P}{\pi\times \frac{8.4^2}{4} }$

$P=13.92\ J.s^{-1}$ is the energy transferred to the eardrums per second.

(B)

mass of mosquito, $m=2\times 10^{-6}\ kg$

<u>Now the velocity of mosquito for the same kinetic energy:</u>

$KE=\frac{1}{2} m.v^2$

$13.92=\frac{1}{2}\times 2\times 10^{-6}\times v^2$

$v=3730.9912\ m.s^{-1}$

(C)

Given:

Sound intensity, $\beta = 20\ dB$

<u>Using eq. (1)</u>

$20=10\ log\ (\frac{I}{10^{-12}} )$

$2=log\ I+12\ log\ 10$

$I=10^{-10}\ W.m^{-2}$

Now, power:

$P=I.A$

$P=10^{-10}\times \pi\times \frac{8.4^2}{4}$

$P=5.54\times 10^{-9}\ J.s^{-1}$

Hence:

$KE=\frac{1}{2} m.v^2$

$5.54\times 10^{-9}=0.5\times 2\times 10^{-6}\times v^2$

$v=0.07444\ m.s^{-1}$

$v=74.44\ mm.s^{-1}$

(D)

mosquitoes speed in part B is very much larger than that of part C.

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3 years ago

a car advertisement states that a certain car that Emily miller loves can accelerates from rest to 70 km/h in 7 seconds. find th

vova2212 [387]

10 km/1 second. Is this what you mean?..

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kotegsom [21]

Answer:

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Explanation:

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liubo4ka [24]

Answer:

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