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3 years ago

Exercising with a friend or partner will enhance your safety. true or false

Physics

2 answers:

bagirrra123 [75]3 years ago

7 0

Exercising with a friend or partner will enhance your safety.

true

Diano4ka-milaya [45]3 years ago

6 0

Yes that is True because if you get injured and your fried Is there he or she can get help

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A man dropped a dime in a wishing well , he heard it 5 sec later ..Find distance traveled if moving at 10 m/s 2

Alenkasestr [34]

Answer:

The distance traveled is 109.58 m

Explanation:

The Speed of sound in air = 344 m/s

Let the time in which the dime dropped by the man reach an impact in the well = t₁

Let the time in which the sound travel from the well to the man = t₂

Then

1/2× 10 × t₁² = 344 × t₂ which gives;

5 × t₁² = 344 × t₂.........................(1)

Also the total time before the man heard the dime = t₁ + t₂ = 5

Therefore;

t₂ = 5 - t₁

Substituting the value of t₂ in equation (1), we have;

5 × t₁² = 344 × (5 - t₁)

5·t₁² + 344·t₁ - 1720 = 0

Using the quadratic formula, we have;

$x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$

Which gives;

$t_1 = \dfrac{-344\pm \sqrt{344^{2}-4\times 5\times (-1720)}}{2\times 5}$

t₁ = 4.68 s or -73.48 s

Therefore, with the positive value for t₁ = 4.68 s, we have

The distance = 1/2× 10 × 4.68² = 109.58 m

The distance traveled = 109.58 m.

8 0

4 years ago

A person in a kayak starts paddling, and it accelerates from 0 to 0.680 m/s in a distance of 0.428 m. If the combined mass of th

d1i1m1o1n [39]

Answer:

Net force, F = 44.66 N

Explanation:

It is given by,

Initial velocity of the person, u = 0

Final velocity of the person, v = 0.68 m/s

Distance, s = 0.428 m

Combined mass of the person and the kayak, m = 82.7 kg

We need to find the net force acting on the kayak i.e.

F = ma...........(1)

Firstly, we will calculate the value of "a" from third equation of motion as :

$v^2-u^2=2as$

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{(0.68\ m/s)^2-0}{2\times 0.428\ m}$

$a=0.54\ m/s^2$

Put the value of a in equation (1) as :

$F=82.7\ kg\times 0.54\ m/s^2$

F = 44.66 N

So, the net force acting on the kayak is 44.66 N. Hence, this is the required solution.

6 0

3 years ago

A 9.0 cm object is 3.0 cm from a lens, which has a focal length of –12.0 cm.

artcher [175]

The answers are -2.4 for the distance. 7.2 for the height. Concave for the type

7 0

3 years ago

Read 2 more answers

Extend the life of your __________ by avoiding fast starts, stops and sharp turns.

skelet666 [1.2K]

Answer:

Tires.

Explanation:

There are the few steps which are discussed below should be taken to increase or extend the life of tires.

(1) Avoid fast starts: Fast start of the vehicle will increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.

(2) Avoid fast stop: Fast stop of the vehicle will also increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.

(3) Avoid sharp turns: The alignment of the wheels and tires are in such a way that they work properly when vehicle is drive in a straight path but sharp turn will increase the uneven pressure on the tires will lead to decrease the life of tires.

Therefore, the life of tires can be extend by avoiding all the above mention actions such as fast stop, start and sharp turns.

5 0

3 years ago

What constant acceleration, in SI units, must a car have to go from zero to 60 mph in 10 s? How far has the car traveled when it

nalin [4]

Answer:

Explanation:

initial velocity, u = 0

final velocity, v = 60 mph = 26.8 m/s

time t = 10 s

Let a be the acceleration and s be he distance traveled.

Use first equation of motion

v = u + a t

26.8 = 0 + a x 10

a = 2.68 m/s

Use second equation of motion

s = ut + 1/2 at²

s = 0 + 0.5 x 2.68 x 10 x 10

s = 134 m

As, 1 m = 3.28 ft

So, s = 134 x 3.28 ft

s = 439.6 ft

7 0

3 years ago