Both the technician are correct.
All the driving force in the universe always flow from the higher body to lower body, until unless acted by external forces. Which means heat always flow from a hotter body to colder body, high pressure always flow to low pressure.
Therefore the both the technician are correct.
The complete question is as follows: A student is subjected to a reaction force of 10 N northward from a 5 kg block while pushing the block over a smooth, level surface. Ignoring friction, what is the acceleration of the block?
Answer: The acceleration of the block is
.
Explanation:
Given: Force = 10 N
Mass = 5 kg
It is known that force applied on an object is the product of mass and acceleration.
Mathematically, 
where,
F = force
m = mass
a = acceleration
Substitute the values into above formula as follows.
Thus, we can conclude that the acceleration of block is
.
<span>Magnetic field lines form circles that go around the wire.</span>
Answer:

Explanation:
Height of the hose pipe is given as

horizontal distance is given as

angle of elevation is given as 35 degree with the horizontal
now we know that the horizontal distance moved is given as


now we have

also we have



so we have

Answer:
A
Explanation:
Finish-Start
Finish to Start is a Logical Relationship in which a Successor Activity cannot start until a Predecessor Activity has finished. What it really means in simple terms we can say that, the Start of a Successor Activity is Dependent on Finish of the Predecessor Activity.
The acquisition of all supplies which is the predecessor activity must finish before the electicalmwork can start which is the successor activity.