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Evgen [1.6K]
3 years ago
13

1. Describe what conversation of momentum means.

Physics
2 answers:
MakcuM [25]3 years ago
7 0

Explanation:

<em>1</em><em>.</em><em> </em><em>Conservation</em><em> </em><em>of</em><em> </em><em>momentum</em><em>,</em><em> </em><em>general awareness</em><em> </em><em>of</em><em> </em><em>physics</em><em> </em><em>according</em><em> </em><em>to</em><em> </em><em>which</em><em> </em><em>the</em><em> </em><em>quantity</em><em> </em><em>called</em><em> </em><em>momentum</em><em> </em><em>that</em><em> </em><em>characteri</em><em>z</em><em>es</em><em> </em><em>motion</em><em> </em><em>never</em><em> </em><em>changes</em><em> </em><em>in</em><em> </em><em>an</em><em> </em><em>isolated</em><em> </em><em>collection</em><em> </em><em>of</em><em> </em><em>objects</em><em>.</em><em> </em>

Snowcat [4.5K]3 years ago
3 0

Answer:

1. The conversation of momentum is when a person or object has momentum and transfers it to another person or object.

Explanation:

2. Like if someone is on a swing and kicks someone in front of him. He stops and the kid in front of him falls over because the momentum was transferred.

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How efficient is a pulley system if it enables you to lift a 600.0 Newton engine 0.600 meters if you exerted 35.7 Newtons of for
muminat

Answer:

η = 0.882 = 88.2 %

Explanation:

The efficiency of the pulley system can be given as follows:

\eta = \frac{W_{out}}{W_{In}}\\\\

where,

η = efficiency of pulley system = ?

W_out = Output Work = (600 N)(0.6 m) = 360 J

W_in = Input Work = (35.7 N)(11.43 m) = 408.051 J

Therefore,

\eta = \frac{360\ J}{408.051\ J}

<u>η = 0.882 = 88.2 %</u>

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3 years ago
What is the speed of a wave with a wavelength of 3 m and a frequency of .1Hz?
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We know,
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3 years ago
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I believe it is angles

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3 years ago
A pin fin of uniform, cross-sectional area is fabricated of an aluminum alloy (k = 160 W/m-K). The fin diameter is D = 4 mm, and
frozen [14]

Answer:

Given that

D= 4 mm

K = 160 W/m-K

h=h = 220 W/m²-K

ηf = 0.65

We know that

m=\sqrt{\dfrac{hP}{KA}}

For circular fin

m=\sqrt{\dfrac{4h}{KD}}

m=\sqrt{\dfrac{4\times 220}{160\times 0.004}}

m = 37.08

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0.65=\dfrac{tanh37.08L}{37.08L}

By solving above equation we get

L= 36.18 mm

The effectiveness for circular fin given as

\varepsilon =\dfrac{2\ tanhmL}{\sqrt{\dfrac{hD}{K}}}

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5 0
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