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4 years ago

A dotted half note has beats when the time signature is 4/4

Physics

2 answers:

levacccp [35]4 years ago

8 0

A dotted half note has 3 beats in 4/4

AfilCa [17]4 years ago

3 0

There is 2 beats on a half note

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A force of 50 N stretches a string by 4 cm,calculate the elastic constant.

murzikaleks [220]

Answer:

50/0.04= answer

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3 years ago

A 146N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 deg

vfiekz [6]

Answer:

F = force

f = friction

u = coefficient of friction

R = normal reaction force

a = Acceleration

m = mass of block

g = gravity

f = uR

F = Ma

Say the block is moving to the right.

The 146N force thus acts to the right, and the friction force to the left, since it resists movement.

The 146N force acts to the right, but the horizontal component of it is 146 cos 50 = 93.84: So this is the force to the right.

Since F = uR and we're trying to find u, we need both F and R. R is easy to get since it is just m x g. This is in fact already given as the weight 350N. So R = 350.

The block is moving at a constant speed, so the force to the right must = the force to the left.

F = ma, so 93.84 - f = (350/g) x 0

This means f must be 93.84 also.

so we have f = uR,

93.84 = u x 350

so u = 0.268 or

0.27 to 2dp.

Hope you understand this.

Explanation:

7 0

3 years ago

The position-time graph describes the motion of a moving object. Describe the motion represented by each segment of the graph.

Marrrta [24]

Answer:

to much sorry.

Explanation:

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3 years ago

In an insulated container, liquid water is mixed with ice. What can you conclude about the phases present in the container when

Ann [662]

Answer:

d. There is no way of knowing the phase composition without more information.

Explanation:

There is no way to ascertain the phases present in the container when equilibrium is established because we are not furnished with enough information.

The most important information needed to have a deeper understanding and provide solution is temperature.
Liquid water and ice can both exist at the same temperature.
So we cannot conclude based on the information at hand.

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3 years ago

When it orbited the moon, the apollo 11 spacecraft's mass was 10400 kg, its period was 133 min, and its mean distance from the m

Anna11 [10]

Since the orbit is circular and you are given the period and average distance( in other words the radius of the orbit) we can calculate the orbital speed right away. Keep in mind that ship's mass is much smaller than the mass of the moon, this is really important, as we can simply say that moon is not affected by the ship.
Angular frequency and orbital speed have the following relationship:
$v=wr=\frac{2\pi}{T}\cdot r$
$v=\frac{2\pi}{133\cdot 60}1.99345\cdot 10^6=1569.5795\frac{m}{s}$
Let's do the calculation with rest of the numbers just to make sure.
Because you have the stable circular orbit the gravitational force and centrifugal force are in balance:
$G\frac{mM}{r^2}=m\frac{v^2}{r}$
We solve this for v:
$G\frac{M}{r}=v^2\\ v=\sqrt{G\frac{M}{r}}$
You can use this formula for any celestial body as long as the ship's mass is much smaller than the mass of the body, and this only applies to circular orbits
When we plug in the numbers we get:
$v=1569.5799\frac{m}{s}$
As you can see the results are identical.

6 0

3 years ago