Answer:
Pressure will decrease according to the Charles Gay Lussac law.
Explanation:
When there is a gas in a tank, and the moles of gas are not modified, neither the volume, we can notice that pressure will be modifying, in order to the absolute temperature, as directly proportion.
T° increase → Pressure increase
T° decrease → Pressure decrease
If the pressure keeps on constant, it will be the volume that would be modified according to the absolute T°, as a directly proportion.
Volume increase → T° increase
Volume decrease → T° decrease
Let's go to the maths
P₁ / T₁ = P₂/T₂
100 kPa / 333K = P₂ / 283K
(100 kPa / 333K) . 283K = P₂ → 84.9 atm
As T° has decreased, pressure also decreased.
Answer:
0.067M H3PO4
Explanation:
H3PO4 reacts with NaOH as follows:
H3PO4 + 3NaOH → 3H2O + Na3PO4
<em>Where 1 mole of H3PO4 reacts with 3 moles of NaOH</em>
To solve trhis question we need to find the moles of NaOH required. With the chemical equation we can find the moles of H3PO4 and its concentration as follows:
<em>Moles NaOH:</em>
50.0mL = 0.0500L * (0.20moles /L) = 0.0100 moles NaOH
<em>Moles H3PO4: </em>
0.0100 moles NaOH * (1mol H3PO4 / 3mol NaOH) = 0.00333 moles H3PO4
<em>Concentration:</em>
0.00333 moles H3PO4 / 0.0500L = 0.067M H3PO4
Answer:
83.33 m/s^2
Explanation:
Acceleration is defined as the rate of change of velocity.
So if we know that at the beginning an object has a velocity V1.
And after a time T, the object has a velocity V2, then the average acceleration in that time interval can be calculated as:
A = (V2 - V1)/T
In this case, we know that the initial speed was 5,000 m/s
And after a time of 60 s, the velocity is 10,000 m/s
Then we have:
V1 = 5,000 m/s
T = 60s
V2 = 10,000 m/s
Then the average acceleration is:
A = (10,000 m/s - 5,000 m/s)/60s = 83.33 m/s^2
The answer is Law of _conservation_ of Energy