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2 years ago

2. What is the resistance expected on a heater that is feed by 480V AC and the Electric Power is 4.6kW?

Physics

1 answer:

Korvikt [17]2 years ago

3 0

The resistance expected of the heater is 50.1 ohms.

<h3>What is resistance?</h3>

Resistance can be defined as the opposition to the flow of electric current in an electric circuit. The S.I unit of resistance is Ohms (Ω).

To calculate the resistance of the heater, we use the formula below.

<h3>Formula:</h3>

R = V²/P............. Equation 1

Where:

R = Resistance of the heater
P = Power of the heater
V = Voltage supplied to the heater

From the question,

Given:

V = 480 V
P = 4.6 kW = 4600 W

Substitute these values into equation 1

R = (480²)/4600
R = 50.1 ohms.

Hence, the resistance expected of the heater is 50.1 ohms.

Learn more about resistance here: brainly.com/question/17563681

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Answer:

tex]\lambda_{Be}[/tex] = 22.78 nm

Explanation:

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$E_{n}$ = k e² / 2a₀ (1 /n²)

ao = h'² / k m e² h' = h/2πi

For another atom with a single electron in the last layer

a₀ ’= h’² / k m (Ze)²

a₀ ’= a₀ / Z²

Therefore, when replacing in the equation

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Let's relate this expression to the wavelength

c = λ f

E = h f

E = h c /λ

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λ = 1 / Z² λ_hydrogen

Let's apply this last equation to our case

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$E_{n}$ = - 9 Eo / n²

40.5 10-9 = 1/9 λ_hydrogen

Beryllium Z = 4

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Let's write our two equations is and solve

40.5 10-9 = 1/9 λ_hydrogen

tex]\lambda_{Be}[/tex] = 1/ 16 λ_hydrogen

40.5 10⁻⁹ = 1/9 (16 $\lambda_{Be}$ )

tex]\lambda_{Be}[/tex] = 40.5 9/16

tex]\lambda_{Be}[/tex] = 22.78 nm

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3 years ago

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<h2>ANSWERS </h2>

1) The relationship in between the electrical energy carriesd by the transmission wires and the amount of the heat loss in it is due to the reason that when the electricity is flown through the wires there are some resistance found in these wires which creates a disturbance in the efficient flow of electricty.Also we know that current have an heating effect when it is in motion as due to if a large amount or magnitude of electricity is flown through the transmission wires it will carry a larger heat effected and also due to the resistance is provided by the wires and so the process of heat loss takes place.

2)It is important to minimize current in transmission wires due to minimize the heat loss and resistance on flowing electric current to make the system more efficient 

 3)Given Resistance = 250 ohms 

Electric potential = 150 volts 

so we know Power = 

volt^2/Resistance = 

=(150^2/250)(ohms/volts)

=(22500/250)watt = 90 watt 

4)Heat energy (H) = Power(P)×Time(t)

4)Heat energy (H) = Power(P)×Time(t)= (90×2)joules = 180 joules

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3 years ago

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Marta_Voda [28]

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3 years ago

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<h2>Answer:</h2>

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<h2>Explanation:</h2>

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3 years ago

Two forces F1 and F2 act on an object at a point P in the indicated directions. The magnitude of F1 is 15 lb and the magnitude o

adoni [48]

Answer

given,

F₁ = 15 lb

F₂ = 8 lb

θ₁ = 45°

θ₂ = 25°

Assuming the question's diagram is attached below.

now,

computing the horizontal component of the forces.

F_h = F₁ cos θ₁ - F₂ cos θ₂

F_h = 15 cos 45° - 8 cos 25°

F_h = 3.36 lb

now, vertical component of the forces

F_v = F₁ sin θ₁ + F₂ sin θ₂

F_v = 15 sin 45° + 8 sin 25°

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resultant force would be equal to

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$F = \sqrt{3.36^2+13.98^2}$

F = 14.38 lb

the magnitude of resultant force is equal to 14.38 lb

direction of forces

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$\theta =tan^{-1}(\dfrac{13.98}{3.36})$

θ = 76.48°

3 0

3 years ago

2. What is the resistance expected on a heater that is feed by 480V AC and the Electric Power is 4.6kW? ​

2. What is the resistance expected on a heater that is feed by 480V AC and the Electric Power is 4.6kW?