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2 years ago

2. What is the resistance expected on a heater that is feed by 480V AC and the Electric Power is 4.6kW?

Physics

1 answer:

Korvikt [17]2 years ago

3 0

The resistance expected of the heater is 50.1 ohms.

<h3>What is resistance?</h3>

Resistance can be defined as the opposition to the flow of electric current in an electric circuit. The S.I unit of resistance is Ohms (Ω).

To calculate the resistance of the heater, we use the formula below.

<h3>Formula:</h3>

R = V²/P............. Equation 1

Where:

R = Resistance of the heater
P = Power of the heater
V = Voltage supplied to the heater

From the question,

Given:

V = 480 V
P = 4.6 kW = 4600 W

Substitute these values into equation 1

R = (480²)/4600
R = 50.1 ohms.

Hence, the resistance expected of the heater is 50.1 ohms.

Learn more about resistance here: brainly.com/question/17563681

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So, 1 N = 1 Kg × 1 m/s^2.

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Hope you could get an idea from here.

Doubt clarification - use comment section.

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3 years ago

2. What is the resistance expected on a heater that is feed by 480V AC and the Electric Power is 4.6kW? ​

2. What is the resistance expected on a heater that is feed by 480V AC and the Electric Power is 4.6kW?