K = Ka/Kb
<h3>
Further explanation</h3>
<u>Given:</u>
<u>Question:</u>
Write the equilibrium constant for this reaction:

in terms of the equilibrium constants, Ka and Kb
<u>The Process:</u>
Let us solve the problem above.
... (Equilibrium-1)
... (Equilibrium-2)
Consider the reaction: 
Equilibrium-2 is reversed to match the target reaction (Hint: PCl₃). Then the two equilibrium reactions are added together.
... (Equilibrium-1)
... (Equilibrium-2, after reversed)
---------------------------------------------------------------- (+)

<u>Notes:</u>
is eliminated.
.- If the two equilibrium reactions are added together, the equilibrium constants are multiplied by each other.
Thus, the equilibrium constant for the target reaction in terms of the equilibrium constants, Ka and Kb, is

<h3>Learn more</h3>
- Conservation of mass brainly.com/question/9473007
- About electrolyte and nonelectrolyte solutions brainly.com/question/5404753
- How many liters of the 50% solution and how many liters of the 90% solution will be used? brainly.com/question/13034221
Keywords: consider the reaction, P, Cl2, PCl3, PCl5, Ka, Kb, K, write, the equilibrium constant, for this, in terms, reverse, multiply