Answer:
Explanation the third one for the second question
A) When a charge is moved in an electric field the work done (W) is calculated as charge*(change in potential). We can write W = q*V or V = W/q = 10/1 = 10V . This voltage is a difference in electric potential between 2 points within the field. If the charge is positive, and positive work is done upon it, then the final position is more positive than the original one.
<span>b) If a charge (Q) is released from rest and falls through a potential difference V, then its gain in energy (KE if no other force acts on the charged body) is q*V = 10J. This is the same as the work done in moving the charge to its new position in part (a), and is an example of the conservation of energy.</span>
<span>First you need to </span>find<span> the slope of the </span>two lines<span>. Because they are </span>parallel<span>, they are the same slope, so if you </span>find<span> the slope of one, you have the slope of both. Start at the \begin{align*}y-\end{align*}intercept of the top </span><span>line.</span>
