Answer:
a) C= 1/120
b) P(X>=5) = 0.333
Explanation:
The attached file contains the explanation for the answers
A balanced three-phase wye-connected generator has an internal impedance of 0.2 + j0.5 Ωper phase and the phase to neutral volta
ge is 220 V. The generator feeds a balanced three-phase wye-connected load having a load impedance of 10 + j8 Ωin each phase. The impedance of the line connecting the generator to the load is 0.2 + j0.8 Ωin each line. The a-phase internal voltage of the generator is specified as the reference phasor.1. Construct a phase equivalent circuit of the system.2. Calculate the line currents ILA, ILB, and ILC.3. Calculate the phase voltages at the load, VAN, VBN, and VCN.4. Calculate the line voltages VAC, VBC, and VCAat the load terminals.5. Calculate the phase voltages at the generator terminals, Van, Vbn, and Vcn.6. Calculate the line voltages at the generator terminals, Vab, Vbc, and Vca.
1 answer:
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Answer:
Compute the number of gold atoms per cubic centimeter = 9.052 x 10^21 atoms/cm3
Explanation:
The step by step and appropriate substitution is as shown in the attachment.
From number of moles = Concentration x volume
number of moles = number of particles/ Avogadro's number
Volume = mass/density, the appropriate derivation to get the number of moles of atoms
