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Delicious77 [7]
3 years ago
6

A boy pulls a sled 46 m across a flat field with a force of 120 N. The force acts on the sled through a rope at a 23° angle with

the horizontal. What is the work the boy does on the sled? (Round your answer to two significant figures.)
Physics
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

5520

Explanation:

w=f×d

w=120×46

w=5.52×10^3

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Longitudinal waves or better known as pressure waves
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Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1200 kg and was approaching at
igomit [66]

To resolve point A and B we need the concepts related to conservation of momentum (By collision) and Kinetic Energy. Conservation of momentum is given by the equation,

m_1\vec{v_1}+m_2\vec{v_2} = (m_1+m_2)\vec{v}

Our values in the statment are:

m_1 = 1200kg

v_1 = 6m/s

m_2 = 900kg

v_2 = 24m/s

Part A) As it is in an icy intersection, there is two different components (x,y) then,

1200(-6\hat{j})+900(-24\hat{i}) = (1200+900)\vec{v}

2100\vec{v} = -21600\hat{i}-7200\hat{j}

\vec{v} = -72/7\hat{i}-24/7\hat{j}

Then the magnitude is,

|\vec{v}| = 9.6525m/s

Part B) To obtain the Kinetic Energy Loss we need to use its equation, which is given by,

KE_i = \frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2

KE_i = \frac{1}{2}(1200)(6)^2+\frac{1}{2}(900)(24)^2

KE_i = 280.8kJ

The final energy is given by,

KE_f = \frac{1}{2}(m_1+m_2)v_f^2

KE_f = \frac{1}{2} (1200+900)(9.65)

KE_f =97778.625J

Then the change in Kinetic Energy is

\Delta KE = KE_f-KE_i = 97.778kJ- 280.8kJ

\Delta KE = -183.02kJ

<em>There was a loss of KE of 183.02kJ</em>

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3 years ago
How are reflecting telescopes similar to devices that produce laser light?
Novosadov [1.4K]

Answer:a

Explanation:

Because its light

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What is velocity ???​
Yuri [45]

Explanation:

“Speed in a definite direction is called velocity.”

5 0
2 years ago
Read 2 more answers
The equipotential surfaces surrounding a point charge are concentric spheres with the charge at the center. If the electric pote
tester [92]

Answer:

1.06 m

Explanation:

Since the charge is at the centre of two concentric spheres, we use the formula for electric potential due to a point charge. V = kq/r. Let r₁ be the radius of the sphere with potential, V₁ = 200 V and  r₂ be the radius of the sphere with potential, V₂ = 82.0 V. From V = kq/r, r = kq/V. So that r₁ = kq/V₁ and r₂ = kq/V₂. The magnitude of the difference r₁ - r₂ is the distance between the two surfaces. q the charge equals 1.63 × 10⁻⁸ C

r₂ - r₁ = kq/V₂ - kq/V₁ = kq(1/V₂ - 1/V₁) = 1.63 × 10⁻⁸ × 9 × 10⁹ (1/82 -1/200) m =  1.63 × 10⁻⁸ × 9 × 10⁹ (0.0122 - 0.005) = 1.63 × 10⁻⁸ × 9 × 10⁹(0.0072) m = 1.06 m

The distance between them is 1.06 m

8 0
3 years ago
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