Answer:
0.667 per day.
Explanation:
Our values here are
Degradation constant=k and is unknown.
We calculate the concentration through the formula,
Replacing values we have
That is the degradation constant of Z-contaminant
An airplane is cruising at a velocity of 800 km/h in air whose density is 0.526 . The airplane has a wing planform area of 90 .
1 answer:
Complete question:
An airplane is cruising at a velocity of 800 km/h in air whose density is 0.526 kg/m³ . The airplane has a wing planform area of 90 m² . The lift and drag coefficients on cruising conditions are estimated to be 2.0 and 0.06, respectively. The power that needs to be supplied to provide enough trust to overcome wing drag is
Answer:
The power that needs to be supplied to provide enough trust to overcome wing drag is 15,600 kW.
(C) 15,600 kW
Explanation:
Given;
velocity of the airplane, v = 800 km/h = 222.22 m/s
density of air, ρ = 0.526 kg/m³
wing planform area, A = 90 m²
lift coefficients, CL = 2.0
drag coefficients, CD = 0.06
Power supplied = FD* V
This is approximately 15,600 kW.
Therefore, The power that needs to be supplied to provide enough trust to overcome wing drag is 15,600 kW.
The correct option is C
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Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7
<h3>How to solve for the value of s2 - s1</h3>
We have
=
v2 = 5x2 - 3x2 + c
= 10-6+c
= 4+c
S2 - S1
= 6 + 6+c - 2+3+c
12+c-5+c = 0
7 = c
Read more on acceleration here: brainly.com/question/605631
Answer:
The mass flow rate of refrigerant is 0.352 kg/s
Explanation:
Considering the cycle of an ideal heat pump, provided in the attachment, we first find enthalpy at state B and D. For that purpose, we use property tables of refrigerant R134a:
<u>At State A</u>:
From table, we see the enthalpy and entropy value of saturated vapor at 0.2 MPa. Therefore:
ha = 244.5 KJ/kg
Sa = 0.93788 KJ/kg.k
<u>At State B</u>:
Since, the process from state A to B is isentropic. Therefore,
Sb = Sa = 0.93788 KJ/Kg
From table, we see the enthalpy value of super heated vapor at 1 MPa and Sb. Therefore:
hb = 256.85 KJ/kg (By interpolation)
<u>At State C</u>:
From table, we see the enthalpy and entropy value of saturated liquid at 1 MPa. Therefore:
hc = 107.34 KJ/kg
Now, from the diagram it is very clear that:
Heat Loss = m(hb = hc)
m = (Heat Loss)/(hb - hc)
where,
m = mass flow rate = ?
Heat Loss = (180,000 Btu/hr)(1.05506 KJ/1 Btu)(1 hr/3600 sec)
Heat Loss = 52.753 KW
Therefore,
m = (52.753 KJ/s)/(256.85 KJ/kg - 107.34 KJ/kg)
<u>m = 0.352 kg/s</u>
