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Alex Ar [27]
3 years ago
14

the capacitor is initially unchanged. immediatley after the switches closes, the capacitor voltage is

Physics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

Immediately after the switches closes, the capacitor voltage is zero.

Explanation:

Charge on capacitor is given as;

q_o = CV_{battery}

after the switches closes, the charge on the capacitor is the same as before, therefore, the voltage drop in the capacitor is zero.

Apply Kirchoff's voltage rule for short term;

q = q_o = 0 (since it is uncharged)

V_{battery} + IR =0

Where;

q₀ is the charge on the capacitor before

q is the charge on the capacitor after

Therefore, immediately after the switches closes, the capacitor voltage is zero.

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Answer:

 W = 9.93 10² N

Explanation:

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           V = A L

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let's calculate

          V = π (4² - 2²) 10⁻⁴  3

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3 years ago
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Answer:

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Explanation:

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4 years ago
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