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MArishka [77]
3 years ago
13

The force of gravity will make it easier to stop your car if you are going uphill, and more difficult to stop your car if you ar

e going downhill.
Physics
1 answer:
Vaselesa [24]3 years ago
6 0
The force of gravity will cause your vehicle to speed up when going downhill, and slow down when going uphill. The energy of motion increases proportionally with the increase in weight, and the energy increases proportionally with the square of the increase in speed. Increase with an increase of your kinetic energy. Gravity decreases your kinetic energy when driving uphill and increases it when driving downhill. Therefore, the force of gravity will make it easier to stop your car if you're going uphill but more difficult to stop your car if you're going downhill.
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What frequency is received by a person watching an oncoming ambulance moving at 110 km/h and emitting a steady 800-Hz sound from
Strike441 [17]

To develop this problem we will apply the concepts related to the Doppler effect. The frequency of sound perceive by observer changes from source emitting the sound. The frequency received by observer f_{obs} is more than the frequency emitted by the source. The expression to find the frequency received by the person is,

f_{obs} = f_s (\frac{v_w}{v_w-v_s})

f_s= Frequency of the source

v_w= Speed of sound

v_s= Speed of source

The velocity of the ambulance is

v_s = 119km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

v_s = 30.55m/s

Replacing at the expression to frequency of observer we have,

f_{obs} = 800Hz(\frac{345m/s}{345m/s-30.55m/s})

f_{obs} = 878Hz

Therefore the frequency receive by observer is 878Hz

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3 years ago
Which of the following is not a way to make exercising on a cold day safer?
IRISSAK [1]

Answer:

D.

Explanation:

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4 0
3 years ago
Read 2 more answers
A 0.50 kg toy is attached to the end of a 1.0 m very light string. The toy is whirled in a horizontal circular path on a frictio
xenn [34]

Answer:

The maximum speed will be 26.475 m/sec

Explanation:

We have given mass of the toy m = 0.50 kg

radius of the light string r = 1 m

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We have to find the maximum speed without breaking the string  

For without breaking the string tension must be equal to the centripetal force

So T=\frac{mv^2}{r}

So 350=\frac{0.5\times v^2}{1}

v^2=700

v = 26.475 m /sec

So the maximum speed will be 26.475 m/sec

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3 years ago
What is the magnification of an object that is 4.15 m in front of a camera that has an image position of 5.0 cm?
Stolb23 [73]
-0.012

Done !!!!!!!!
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