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Elza [17]
3 years ago
13

1. In an atom, an electron and a proton are separated by a distance of 1 x 10-8m. a) Find the force on the electron. b) Assuming

a circular orbit (which wouldn't happen, but we'll go with it). Find the velocity of the electron.
Physics
1 answer:
aleksandrvk [35]3 years ago
6 0

Answer:

(a) 2.3 x 10^-12 N

(b) 1.6 x 10^5 m/s

Explanation:

q1 = 1.6 x 10^-19 C

q2 = 1.6 x 10^-19 C

r = 1 x 10^-8 m

(a) the electrostatic force is given by

F = K q1 x q2 / r^2

F = ( 9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (1 x 10-^-8)^2

F = 2.3 x 10^-12 N

The force is attractive in nature because the nature of charge on electron and proton s opposite to each other.

(b) The electrostatic force is balanced by the centripetal force actig on the electron.

F = mv^2 / r

where, r be the radius of orbit and v be the velocity of electron in the orbit.

2.3 x 10^-12 = (9.1 x 10^-31 x v^2) / (1 x 10^-8)

v = 1.6 x 10^5 m/s

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| Impedance | = √ [R² +(ωL)²]

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          = 2.0884 x 10⁻⁴  f²

| Z | =  √[ (4.624 x 10⁷) + (2.0884 x 10⁻⁴ f²) ]  =  1.6 x 10⁵

     (1.6 x 10⁵)²  =  (4.624 x 10⁷) + (2.0884 x 10⁻⁴ f²)

     (2.56 x 10¹⁰) - (4.624 x 10⁷)  =  2.0884 x 10⁻⁴ f²


Frequency² =   (2.56 x 10¹⁰ - 4.624 x 10⁷)  /  2.0884 x 10⁻⁴

                    =       2.555 x 10¹⁰ / 2.0884 x 10⁻⁴

                    =          1.224 x 10¹⁴ 

                    =          122,400 GHz          <== my calculation

                                      11.1 MHz           <== online impedance calculator

Obviously, I must have picked up some rounding errors
in the course of my calculation. 
  











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