The diagram shows a wave traveling through a medium. Identify point B.
1 answer:
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Answer:
The strength of the magnetic field is .
Explanation:
Given that,
Length of the rod, L = 1.01 m
Speed with which the rod is moving, v = 3.47 m/s
We need to find the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.265 mV across the rod. When the rod is moving with some speed, an emf gets induced and it is given by :
B is magnetic field
So, the strength of the magnetic field is .
Answer:
Magnitude of electric field is 1.06 x V/m along negative X-direction
Explanation:
Given: initial velocity of proton = u = 3.5 x m/s
final velocity of proton = v = 0 m/s
initial point = 0.2 m and final point is
= 0.8 m
According to conservation of energy:
change in in kinetic energy = change in potential energy of proton
⇒
where q and m is the charge and mass of proton E is the electric field , and
is the initial and final position of proton
on substituting the respected values we get,
1.023 x = 9.6 x
x E
⇒ E = 1.06 x V/m
external force is opposite to the motion as velocity of proton decreases with distance.
Therefore, magnitude of electric field is 1.06 x V/m along negative X-direction