Answer:
Draw the vector triangle (head to tail)
Let 8 be adjacent and 4 the opposite side
tan theta = 4 / 8 = .5
theta = 26.6 deg
Answer:
Explanation:
Given
time taken 
Speed acquired in 2 sec 
Here initial velocity is zero 
acceleration is the rate of change of velocity in a given time


Distance travel in this time

where
s=displacement
u=initial velocity
a=acceleration
t=time


so Jet Plane travels a distance of 42 m in 2 s
Answer:
A measured force of (46.5 0.8 N ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N )
Explanation:
From the question we are told that
Measured force is ![F_M = [46.5 \pm 0.8 \ N ]](https://tex.z-dn.net/?f=F_M%20%20%3D%20%20%5B46.5%20%5Cpm%200.8%20%5C%20%20N%20%5D)
Calculated force is ![F_c = [48.4 \pm 0.6 \ N ]](https://tex.z-dn.net/?f=F_c%20%3D%20%20%5B48.4%20%5Cpm%200.6%20%5C%20%20N%20%5D)
Generally the measured force in interval form is

=> 
Generally the calculated force in interval form is

=> 
Generally looking both interval we see that they do not intersect at any point Hence
A measured force of (46.5 0.8 N ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N )
Answer:
the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm
Explanation:
Given the data in the question;
wavelength of light; λ = 463 nm = 463 × 10⁻⁹ m
Index of refraction; n = 1.35
Now, the thinnest thickness of the soap film can be determined from the following expression;
= ( λ / 4n )
so we simply substitute in our given values;
= ( 463 × 10⁻⁹ m ) / 4(1.35)
= ( 463 × 10⁻⁹ m ) / 5.4
= ( 463 × 10⁻⁹ m ) / 4(1.35)
= 8.574 × 10⁻⁸ m
= 85.74 × 10⁻⁹ m
= 85.74 nm
Therefore, the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm