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3 years ago

Is it possible for a distance versus-time graph to be a vertical line?

Physics

2 answers:

Phoenix [80]3 years ago

5 0

Answer:

In a distance-time graph, time is on the horizontal axis, or x-axis, and distance is on the vertical axis, or y-axis. As an object moves, the distance it travels increases with time. ... You can use the steepness, or slope, of a line in a distance-time graph to determine the speed of an object if speed is constant.

Explanation:

Feliz [49]3 years ago

4 0

If time is the x axis and distance is the y axis then yes, in the case that time is going by but distance remains the same.

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a fan acquires a speed of 180 rpm in 4s, starting from rest. calculate the speed of the fan at the end of the 5th second startin

KengaRu [80]

Answer:

225 rpm

Explanation:

The angular acceleration of the fan is given by:

$\alpha = \frac{\omega_f - \omega_i}{\Delta t}$

where

$\omega_f$ is the final angular speed

$\omega_i$ is the initial angular speed

$\Delta t$ is the time interval

For the fan in this problem,

$\omega_i = 0\\\omega_f = 180 rpm\\\Delta t=4 s$

Substituting,

$\alpha = \frac{180-0}{4}=45 rpm/s$

Now we can find the angular speed of the fan at the end of the 5th second, so after t = 5 s. It is given by:

$\omega' = \omega_i + \alpha t$

where

$\omega_i = 0\\\alpha = 45 rpm/s\\t = 5 s$

Substituting,

$\omega' = 0 + (45)(5)=225 rpm$

7 0

3 years ago

A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second 2. What is the net force on the car?

Elodia [21]

Newton #2: F = M a

(1 x 10³ kg) (4.5 m/s²) = 4,500 newtons

3 0

3 years ago

Helppp plss

shutvik [7]

Answer:

a) P = 149140[w]; b) 1491400[J]; c) v = 63.06[m/s]

Explanation:

As the solution to the problem indicates, we must convert the power unit from horsepower to kilowatts.

P = 200 [hp]

$200[hp] * 745.7 [\frac{watt}{1 hp}]\\149140[watt]$

Now the power definition is known as the amount of work done in a given time

P = w / t

where:

w = work [J]

t = time [s]

We have the time, and the power therefore we can calculate the work done.

w = P * t

w = 149140 * 10 = 1491400 [J]

And finally, we can calculate the velocity using, the expression for kinetic energy

$E_{k}=w=0.5*m*v^{2}\\ where:\\v = velocity[m/s]\\m=mass=750[kg]\\w=work=1491400[J]\\$

The key to solving this problem is to recognize that work equals kinetic energy

$v=\sqrt{\frac{w}{0.5*m}} \\v=\sqrt{\frac{1491400}{0.5*750}} \\v=63.06[m/s]$

3 0

3 years ago

The color of a star is

never [62]

D determined by its temperature

8 0

4 years ago

Read 2 more answers

How to determine the center of gravity of a lamina

goldenfox [79]

Take a lamina with three holes near the periphery of the lamina, now suspend the lamina through them, one by one. Draw a line of equilibrium for each suspension point. The point of intersection of these three lines would be the centre of gravity.

7 0

2 years ago