The answer is B. Friction is going to the RIGHT because friction works against where you are trying to go
Answer:
1.7323
Explanation:
To develop this problem, it is necessary to apply the concepts related to refractive indices and Snell's law.
From the data given we have to:
![n_{air}=1](https://tex.z-dn.net/?f=n_%7Bair%7D%3D1)
![\theta_{liquid} = 19.38\°](https://tex.z-dn.net/?f=%5Ctheta_%7Bliquid%7D%20%3D%2019.38%5C%C2%B0)
![\theta_{air}35.09\°](https://tex.z-dn.net/?f=%5Ctheta_%7Bair%7D35.09%5C%C2%B0)
Where n means the index of refraction.
We need to calculate the index of refraction of the liquid, then applying Snell's law we have:
![n_1sin\theta_1 = n_2sin\theta_2](https://tex.z-dn.net/?f=n_1sin%5Ctheta_1%20%3D%20n_2sin%5Ctheta_2)
![n_{air}sin\theta_{air} = n_{liquid}sin\theta_{liquid}](https://tex.z-dn.net/?f=n_%7Bair%7Dsin%5Ctheta_%7Bair%7D%20%3D%20n_%7Bliquid%7Dsin%5Ctheta_%7Bliquid%7D)
![n_{liquid} = \frac{n_{air}sin\theta_{air}}{sin\theta_{liquid}}](https://tex.z-dn.net/?f=n_%7Bliquid%7D%20%3D%20%5Cfrac%7Bn_%7Bair%7Dsin%5Ctheta_%7Bair%7D%7D%7Bsin%5Ctheta_%7Bliquid%7D%7D)
Replacing the values we have:
![n_{liquid}=\frac{(1)sin(35.09)}{sin(19.38)}](https://tex.z-dn.net/?f=n_%7Bliquid%7D%3D%5Cfrac%7B%281%29sin%2835.09%29%7D%7Bsin%2819.38%29%7D)
![n_liquid = 1.7323](https://tex.z-dn.net/?f=n_liquid%20%3D%201.7323)
Therefore the refractive index for the liquid is 1.7323
Answer:
<u><em>Electric Potential Energy:</em></u>
The energy that is needed to move a charge against an electric firld is called Electric Potential Energy
<u><em>Electric Potential Difference:</em></u>
The amount of work done in carrying a unit charge from one point to an other in an electric field is called Electric Potential Difference.
<u><em>Relation:</em></u>
Relation between Electric potential and electrical potential energy is given by
![\delta V=\frac{PE}{q}](https://tex.z-dn.net/?f=%5Cdelta%20V%3D%5Cfrac%7BPE%7D%7Bq%7D)
Here PE represents Electric potential energy
and
is Electric potential difference
it means electric potential difference is the difference in electric potential energy divided by the charge.
Answer:
2943 J
Explanation:
Potential energy = mass x acceleration due to gravity x height in meters
(P.E. = mgh)
Substitute the given numbers: (I take acceleration due to gravity as 9.81 m s^-2)
PE = 40 x 9.81 x (0.15x50)
PE = 2943 J