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serg [7]
3 years ago
6

In a nuclear reaction, which of the following must be conserved?

Physics
2 answers:
Oduvanchick [21]3 years ago
8 0

Answer:

c

Explanation:

AfilCa [17]3 years ago
7 0

Answer:

c

Explanation:

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A 0.86 kg rock is projected from the edge of the top of a building with an initial velocity of 8.65 m/s at an angle 46◦ above th
Georgia [21]

Answer:

Height of the building = 11.4 m

Explanation:

As we know that the stone is projected at an angle 46 degree with speed 8.65 m/s

so the two components of the speed is given as

v_x = 8.65 cos46

v_x = 6 m/s

vertical component of the speed is given as

v_y = 8.65 sin46

v_y = 6.22 m/s

now we know that the ball strike at horizontal distance of 13.7 m

so we will have

x = v_x t

13.7 = 6 t

t = 2.28 s

now we know that in vertical direction ball will move under uniform gravity so we can use kinematics

y = v_y t + \frac{1}{2}at^2

y = 6.22(2.28) - \frac{1}{2}(9.81)(2.28^2)

y = -11.4 m

Height of the building = 11.4 m

3 0
3 years ago
Read 2 more answers
April and Alex are saving money to buy new phones. Each friend starts with some money and saves a specific amount each week.
qwelly [4]
First thing to note is that we are on week 0, when they start saving:

The equation for Alex is:

y=20x + 125 

Know that we are on week 0, and x is our weeks, that makes our equation:

y=20(0) + 125 

Which means it's really:

y=125

That means that the first one is E. 125

For the second, it shows our week 0, which is at 100.

That means that the second one is I. 100

Hope this helps!
5 0
4 years ago
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A ball is thrown horizontally from the top of a building 54 m high. The ball strikes the ground at a point 35 m horizontally awa
Ivanshal [37]

Answer:

V=34.2 m/s

Explanation:

Given that

Height , h= 54 m

Horizontal distance , x = 35 m

Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.

In vertical direction :

We know that

V^2_y=U^2_y+2 g h

Now by putting the values in the above equation we got

V^2_y=U^2_y+2 g h

V^2_y=0^2+2\times 9.81 \times 54

Assume g= 9.81 m/s^2

Thus

V^2_y=1059.48

V_y=\sqrt{1059.48}\ m/s

V_y=32.54 m/s

We also know that

V_y=U_y+ g\times t

32.54=9.81\times t

t=\dfrac{32.54}{9.81}=3.31\ s

In horizontal direction :

x=U_x\times t

U_x=\dfrac{35}{3.31}=10.54\ m/s

Thus the resultant velocity

V=\sqrt{V^2_y+U^2_x}

V=\sqrt{32.54^2+10.54^2}=34.2\ m/s

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5 0
4 years ago
What is the number of electrons to come be held in the first orbit closest to the nucleus
Mariulka [41]
In the first shell there can be a maximum of 2 electrons, then 8o in the second one and 8 in the third one.
6 0
3 years ago
Which two technologies use the same range of radio wave frequencies? television broadcasting and AM radio broadcasting cell phon
Tju [1.3M]
Let us reject some answers. AM and FM radio waves do not interfere. Am are an orders of magnitude larger than FM waves. FM waves belong to microwaves, a subcategory of radiowaves while AM does not. Similarly, AM  and TV have not the same, because TV uses a subset of the frequencies used in FM. The correct answe is that CB radios and submarine communication happen at the same wavelengths/frequencies, namely low frequency radiowaves.
4 0
4 years ago
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