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sineoko [7]
2 years ago
9

Consider a multiprocessor system and a multithreaded program written using the many-to-many threading model. Let the number of u

ser-level threads in the program be more than the number of processors in the system. Discuss the performance implications of the following scenarios.
The number of kernel threads allocated to the program is less than the number of processing cores
The number of kernel threads allocated to the program is equal to the number of processing cores
The number of kernel threads allocated to the program is greater than the number of processing cores but less than the number of user-level threads
Engineering
1 answer:
Montano1993 [528]2 years ago
4 0

Answer:

At the point when the quantity of bit strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just part strings to processors and not client level strings to processors. At the point when the quantity of part strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used all the while. Be that as it may, when a part string obstructs inside the portion (because of a page flaw or while summoning framework calls), the comparing processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, in this way expanding the use of the multiprocessor system.When the quantity of part strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just bit strings to processors and not client level strings to processors. At the point when the quantity of bit strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used at the same time. Be that as it may, when a part string hinders inside the piece (because of a page flaw or while summoning framework calls), the relating processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, along these lines expanding the usage of the multiprocessor framework.

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A river has an average rate of water flow of 59.6 M3/s. This river has three tributaries, tributary A, B and C, which account fo
Fiesta28 [93]

Answer:

50421.6 m³

Explanation:

The river has an average rate of water flow of 59.6 m³/s.

Tributary B accounts for 47% of the rate of water flow. Therefore the rate of water flow through tributary B is:

Flow rate of water through tributary B = 47% of 59.6 m³/s = 0.47 * 59.6 m³/s = 28.012 m³/s

The volume of water that has been discharged through tributary B = Flow rate of water through tributary B * time taken

time = 30 minutes = 30 minutes * 60 seconds / minute = 1800 seconds

The volume of water that has been discharged through tributary B in 30 seconds = 28.012 m³/s * 1800 seconds = 50421.6 m³

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Amiraneli [1.4K]
Okay sure.









I’ll 1)chords
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Pretty sure those are the answers
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Risks in driving never begins with yourself, but with other drivers who take risks.
Ymorist [56]

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You want to find all files on your server that have either the SGID or SUID permission set. Which command should you use to obta
aalyn [17]

Answer:

For SGID you type this

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For SUID you type this

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Explanation:

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After typing

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