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sineoko [7]
3 years ago
9

Consider a multiprocessor system and a multithreaded program written using the many-to-many threading model. Let the number of u

ser-level threads in the program be more than the number of processors in the system. Discuss the performance implications of the following scenarios.
The number of kernel threads allocated to the program is less than the number of processing cores
The number of kernel threads allocated to the program is equal to the number of processing cores
The number of kernel threads allocated to the program is greater than the number of processing cores but less than the number of user-level threads
Engineering
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

At the point when the quantity of bit strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just part strings to processors and not client level strings to processors. At the point when the quantity of part strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used all the while. Be that as it may, when a part string obstructs inside the portion (because of a page flaw or while summoning framework calls), the comparing processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, in this way expanding the use of the multiprocessor system.When the quantity of part strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just bit strings to processors and not client level strings to processors. At the point when the quantity of bit strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used at the same time. Be that as it may, when a part string hinders inside the piece (because of a page flaw or while summoning framework calls), the relating processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, along these lines expanding the usage of the multiprocessor framework.

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Print "userNum1 is negative." if userNum1 is less than 0. End with newline. Assign userNum2 with 2 if userNum2 is greater than 1
miv72 [106K]

Answer:

From the question, we have two variables

1. userNum1

2. userNum2

And we are to print "userNum1 is negative" if userNum1 is less than 0.

Then Assign userNum2 with 2 if userNum2 is greater than 10.

Otherwise, print "userNum2 is less or equal 10.".

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main ()

{

// Declare variables

int userNum1, userNum2;

// Accept input for these variables

cin>>userNum1, userNum2;

// Condition 1

if(userNum1 < 0)

{

cout<<"userNum1 is negative"<<'\n';

}

// Condition 2

if(userNum2 > 10)

{

userNum2 = 2;

}

// If condition is less than 10

else

{

cout<<"userNum2 is less or equal to 10"<<\n;

}

return 0;

}

// End of Program.

3 0
3 years ago
What are some of the trade-offs of a move to an enterprise-level analytics solution for individual end users who might have grow
aleksandrvk [35]

Answer:

THE thing is 435

Explanation:

3 0
3 years ago
Ada Lovelace Day, celebrating Ada, Countess of Lovelace as the first computer programmer, is traditionally celebrated on the sec
snow_lady [41]

Ada Lovelace Day, celebrating Ada, Countess of Lovelace as the first computer programmer, is traditionally celebrated on the second Tuesday of October each year is given below

Explanation:

1.The second Tuesday of every October marks Ada Lovelace Day, a day founded in 2009 by technologist Suw Charman-Anderson, to celebrate the achievements of women in Stem careers (science, technology, engineering and mathematics), and was created in memory of one in particular: Ada Lovelace, the first computer programmer.

2.Ada Lovelace: The First Computer Programmer. Ada Lovelace has been called the world's first computer programmer. ... By 1834 he had moved on to design his Analytical Engine, the first general purpose computer, which used punch cards for input and output. This machine also lacked financing and was never built.

3.Born two centuries ago, Ada Lovelace was a pioneer of computing science. She took part in writing the first published program and was a computing visionary, recognizing for the first time that computers could do much more than just calculations.

4.Through Babbage, Ada began studying advanced mathematics with University of London professor Augustus de Morgan. Ada was fascinated by Babbage's ideas. Known as the father of the computer, he invented the difference engine, which was meant to perform mathematical calculations.

5.It's Ada Lovelace Day today which means it is a time to celebrate the achievements of women working in the fields of science, technology, engineering and mathematics (STEM). Now in its eighth year, the annual celebration was founded by journalist and software activist Suw Charman-Anderson.

6 0
3 years ago
How can I solve 23.5 million Nona meters to millimeters using no calculator because I have to show my work
lozanna [386]

Answer:

its so simple. u must mind some formulas.

Explanation:

mili->10^(-3)

micro->10^(-6)

nano->10^(-9)

so write the exact number and move "." to left or right depend question.

in this one:

23.5 is 23500000.0 nano with a default dot at the end

for turning to mili u must move the dot 6 steps to left so it will be: 23.5 milimeter.

6 0
3 years ago
In a parallel one-dimensional flow in the positive x direction, the velocity varies linearly from zero at y = 0 to 32 m/s at y =
monitta

Answer:

Ψ = 10(y^2) + c

<em><u>y = 1.067m</u></em>

Explanation:

since the flow is one dimensional in positive X direction, the only velocity component is in X, which is denoted by u

while u is a function of y

we find the u in terms of y; u varies linearly wih y

we use similiraty to find the relation

32/1.6 =<em>u/y</em>

<em><u>u = 20y</u></em>

<em><u>Ψ = ∫20ydy</u></em>

<em><u>Ψ = 10(y^2) + c</u></em>

<em><u>(b)</u></em>

<em><u>the flow is half below y = 1.6*(2/3)=1.067 m</u></em>

<em><u>this is because at two third of the height of a triangle lies the centroid of triangle. since the velocity profile forms a right angled triangle , its height is 1.6 m . the flow is halved at y = 1.067m</u></em>

3 0
3 years ago
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