Answer:
The inductance of the inductor is 0.051H
Explanation:
From Ohm's law;
V = IR .................. 1
The inductor has its internal resistance referred to as the inductive reactance, X
, which is the resistance to the flow of current through the inductor.
From equation 1;
V = IX
X
=
................ 2
Given that; V = 240V, f = 50Hz,
=
, I = 15A, so that;
From equation 2,
X
= 
= 16Ω
To determine the inductance of the inductor,
X
= 2
fL
L = 
= 
= 0.05091
The inductance of the inductor is 0.051H.
Answer:
Heat required (q) = 471.19kj/kg
Explanation:
Find attached below solution to problem
Answer:
(a) Current density at P is
.
(b) Total current I is 3.257 A
Explanation:
Because question includes symbols and formulas it can be misunderstood. In the question current density is given as below;

where
and
unit vectors.
(a) In order to find the current density at a specific point <em>(P)</em>, we can simply replace the coordinates in the current density equation. Therefore

(b) Total current flowing outward can be calculated by using the relation,

where integral is calculated through the circular band given in the question. We can write the integral as below,

due to unit vector multiplication. Then,

where
. Therefore

Answer:
The change in enthalpy of helium is 4073.86kJ/kg
Explanation:
∆H = Cp(T2 - T1)
Cp = 3.5R = 3.5×8.314 = 29.099kJ/kgmolK ÷ 2 (1kgmol of helium = 2kg of helium) = 14.5495kJ/kgK, T2 = 300°C = 300+273K = 573K, T1 = 20°C = 20+273K = 293K
∆H = 14.5495kJ/kgK(573K - 293K) = 14.5495kJ/kgK × 280K = 4073.86kJ/kg
Answer:
Rubber-like solids with elastic properties are called elastomers. Polymer chains are held together in these materials by relatively weak intermolecular bonds, which permit the polymers to stretch in response to macroscopic stresses. Natural rubber, neoprene rubber, buna-s and buna-n are all examples of such elastomers.