Answer:
The part of the system that is considered the resistance force is;
B
Explanation:
The simple machine is a system of pulley that has two pulleys
The effort, which is the input force at A gives the value of the tension at C and D which are used to lift the load B
Therefore, we have;
A = C = D
B = C + D = C + C = 2·C
∴ C = B/2
We have;
C = B/2 = A
Therefore, with the pulley only a force, A equivalent to half the weight, B, of the load is required to lift the load, B
The resistance force is the constant force in the system that that requires an input force to overcome in order for work to be done
It is the force acting to oppose the sum of the other forces system, such as a force acting in opposition to an input force
Therefore, the resistance force is the load force, B, for which the input force, A, is required in order for the load to be lifted.
Answer:
Check the explanation
Explanation:
Kindly check the attached images below to see the step by step explanation to the question above and also note that I derived the whole expressions in variable firm that are required to solve this question and giving reasons for each step so that you can employ these steps in solving new problems.
Answer:
Fuel efficiency for highway = 114.08 miles/gallon
Fuel efficiency for city = 98.79 miles/gallon
Explanation:
1 gallon = 3.7854 litres
1 mile = 1.6093 km
Let's first convert the efficiency to km/gallon:
48.5 km/litre = (48.5 * 3.7854) km/gallon
48.5 km/litre = 183.5919 km/gallon (highway)
42.0 km/litre = (42.0 * 3.7854) km/gallon
42.0 km/litre = 158.9868 km/gallon (city)
Next, we convert these to miles/gallon:
183.5919 km/gallon = (183.5919 / 1.6093) miles/gallon
183.5919 km/gallon = 114.08 miles/gallon (highway)
158.9868 km/gallon = (158.9868 /1.6093) miles/gallon
158.9868 km/gallon = 98.79 miles/gallon (city)
Answer:
The answer is "83.98, 1889.195, and 1889.195"
Explanation:
Given value:

In point a:
The value of 

In point b:
calculating heat leaves formula= 

In point c:
calculating Heat transfer rate formula
