Answer:
40mph
Explanation:
1st leg DATA:
time = 3 hrs ; speed = r mph ; distance = 3r miles
------------
2nd leg DATA:
speed = r mph ; distance = 12 miles
--------------------------------
3r + 12 = 132
3r = 120
rate = 40 mph
Solar Flares: C
Prominences: A
Sun Spots: D
Convection: B
The minimum speed with which the athlete must leave the ground is 2.21 m/s
From the question given above, the following data were obtained:
- Maximum Height (h) = 0.25 m
- Final velocity (v) = 0 (at maximum height)
- Acceleration due to gravity (g) = 9.8 m/s²
v² = u² – 2gh (going against gravity)
0² = u² – (2 × 9.8 × 0.25)
0 = u² – 4.9
Collect like terms
u² = 0 + 4.9
u² = 4.9
Take the square root of both side
u = √4.9
u = 2.21 m/s
Thus, the athlete must leave the ground with a minimum speed of 2.21 m/s.
Learn more about projectile motion:
brainly.com/question/15604286