Answer:
There is two common methods to separate a phosphorylated protein from the proteins who does not have the phosphate group.
1. Western Blot test
The Western blot test is a method where we separate of the biological sample with SDS- PAGE (electrophoresis method) and then we transfer to a nitrocellulose membrane. We use a phospho-specific antibody to identify the protein of interest.
2. The ELISA test
this test is also a powerful method for measuring protein phosphorylation. Elisa test is more are quantitative than Western blot test and also shows great advantage in studies related with kinase activity. In this test we use a capture antibody specific for the desired protein, independent of the phosphorylation state. The target protein is binded to the antibody-coated plate. and finally a detection antibody specific for the phosphorylation site analyzed is added. In these test it is possible to use colorimetric or fluorometric detection.
Answer:
Mass 1=3M
Mass 2=?
Volume1=75mL
Volume2=250mL
By using molarity formula:
<u>mass1*volume 1=mass2*volume 2</u>
3M*75=mass2*250
mass2=225/250
mass2:0.9M
<h3>the molarity of a solution is 0.9M.</h3>
:CH=CH2, also expressed as H-C=C:
<span>___________________________|__| </span>
<span>___________________________H H </span>
<span>(Sorry about the underscores; the spacing doesn't work if I don't include them) </span>
<span>This compound is a derivative of ethene, which is CH2=CH2. In place of the fourth H atom, CH3 has a lone pair (as shown in the above formula). Or, it can be bonded to another compound as well in that empty spot.</span>
Answer : The mass of helium gas added must be 12.48 grams.
Explanation : Given,
Mass of helium (He) gas = 6.24 g
Molar mass of helium = 4 g/mole
First we have to calculate the moles of helium gas.
Now we have to calculate the moles of helium gas at doubled volume.
According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,
or,
where,
= initial volume of gas = V
= final volume of gas = 2V
= initial moles of gas = 1.56 mole
= final moles of gas = ?
Now we put all the given values in this formula, we get
Now we have to calculate the mass of helium gas at doubled volume.
Therefore, the mass of helium gas added must be 12.48 grams.
