Question

A chemical company makes two brands of antifreeze. The first brand is 35% pure antifreeze, and the second brand is 60% pure antifreeze. In order to obtain 60 gallons of a mixture that contains 45% pure antifreeze, how many gallons of each brand of antifreeze must be used?

Answer 1

Answer:

36 gallons of each first brand and 24 gallons second brand of antifreeze must be used.

Explanation:

Let the volume of two different antifreeze be x and y.

Total volume required = 60 gal

x + y = 60 gal ...(1)

In order to obtain 60 gallons of a mixture that contains 45% pure antifreeze.

$x\times 35\%+y\times 60\%=60 gal\times 45\%$

$35x+60 y=2700 gal$

$7x+12y=540 gal$

On solving equation (1) ans (2), we get:

x = 36 gal, y = 24 gal

36 gallons of each first brand and 24 gallons second brand of antifreeze must be used.