Answer:
(a) (1) -32ft/s
(2) -25.6ft/s
(3) -24.8ft/s
(4) -24.16ft/s
(b) -24 ft/s
Explanation:
First of all, we need the position for every instant mentioned in order to calculate average velocities:
Y(2) = 2 ft
Y(2.5) = 0 ft
Y(2.1) = 13.44 ft
Y(2.05) = 14.76 ft
Y(2.01) = 15.7584 ft
Let's now calculate average velocities:
Now, for the instantaneous velocity, we derive the expression for y:
V(t) = 40 - 32t For t=2s V(2) = -24ft/s
I don't think so it would be some where between 9 and 10
False, you can't use a light bulbs heat for energy.
The ratio of the distance moved by the point at which the effort is applied in a simple machine to the distance moved by the point at which the load is applied, in the same time. In the case of an ideal (frictionless and weightless) machine, velocity ratio = mechanical advantage. Velocity ratio is sometimes called distance ratio.