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lidiya [134]
3 years ago
11

There are 11 lights in series, and they are in series with 2 lights in parallel. If the 13 lights are identical, which of them w

ill burn brightest?
11 lights
2 lights
all 13 lights
none will be brightest
Physics
1 answer:
BlackZzzverrR [31]3 years ago
8 0
<h2>Answer: 2 lights (in parallel)</h2>

Explanation:

When light bulbs are connected in series the total voltage V_{s} will be:

V_{s}=V_{1}+V_{2}+...+V_{n}  (1)

This means the <u>total voltage will be distributed among each of the bulbs</u> in series, therefore the luminosity will be also divided among the bulbs.

When lights are connected in parallel the total voltage V_{p} will be:

V_{p}=V_{1}=V_{2}=...=V_{n}  (2)

This means the <u>total voltage will be the same for each bulbs</u> in parallel, therefore the luminosity will be the same.

Now, if we combine this two types of connections, as in this problem with 11 lights in series, which are also in series with 2 lights in parallel; the 2 lights in parallel will be brighter than the 11 lights in series.

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At what speed should a ball of mass 2 kg be rolled in order to reach the other side of
Veronika [31]

Answer:

M g H = 1/2 M v^2       potential energy = kinetic energy

v^2 = 2 g H = 2 * 9.80 * 6 = 117.6 m/s^2

v = 10.8 m/s    

(C)

6 0
1 year ago
How much energy is stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800
ozzi

Answer:

The energy stored in the solenoid is 7.078 x 10⁻⁵ J

Explanation:

Given;

diameter of the solenoid, d = 2.80 cm

radius of the solenoid, r = d/2 = 1.4 cm

length of the solenoid, L = 14 cm = 0.14 m

number of turns, N = 200 turns

current in the solenoid, I = 0.8 A

The cross sectional area of the solenoid is given as;

A = \pi r^2\\\\A = \pi (0.014)^2\\\\A = 6.16*10^{-4} \ m^2

The inductance of the solenoid is given by;

L = \frac{\mu_0 N^2A}{l} \\\\L =  \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H

The energy stored in the solenoid is given by;

E = ¹/₂LI²

E = ¹/₂(2.212 x 10⁻⁴)(0.8)²

E = 7.078 x 10⁻⁵ J

Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J

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3 years ago
Without heat from the Sun, the water cycle would A) reverse. B) not work. C) slow down. D) not be affected.
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Read 2 more answers
Ultraviolet light having a wavelength of 97 nm strikes a metallic surface. Electrons leave the surface with speeds up to 3.48 ×
irga5000 [103]

Answer:

<h2><em>12.45eV</em></h2>

Explanation:

Before calculating the work function, we must know the formula for calculating the kinetic energy of an electron. The kinetic energy of an electron is the taken as the difference between incident photon energy and work function of a metal.

Mathematically, KE =  hf - Ф where;

h is the Planck constant

f is the frequency = c/λ

c is the speed of light

λ is the wavelength

Ф is the work function

The formula will become KE =  hc/λ - Ф. Making the work function the subject of the formula we have;

Ф = hc/λ - KE

Ф = hc/λ - 1/2mv²

Given parameters

c = 3*10⁸m/s

λ = 97*10⁻⁹m

velocity of the electron v = 3.48*10⁵m/s

h = 6.62607015 × 10⁻³⁴

m is the mass of the electron = 9.10938356 × 10⁻³¹kg

Substituting the given parameters into the formula Ф = hc/λ - 1/2mv²

Ф =  6.63 × 10⁻³⁴*3*10⁸/97*10⁻⁹ -  1/2*9.11*10⁻³¹(3.48*10⁵)²

Ф = 0.205*10⁻¹⁷ - 4.555*10⁻³¹*12.1104*10¹⁰

Ф = 0.205*10⁻¹⁷ - 55.163*10⁻²¹

Ф = 0.205*10⁻¹⁷ - 0.0055.163*10⁻¹⁷

Ф = 0.1995*10⁻¹⁷Joules

Since 1eV = 1.60218*10⁻¹⁹J

x = 0.1995*10⁻¹⁷Joules

cross multiply

x = 0.1995*10⁻¹⁷/1.60218*10⁻¹⁹

x = 0.1245*10²

x = 12.45eV

<em>Hence the work function of the metal in eV is 12.45eV</em>

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