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lidiya [134]
3 years ago
11

There are 11 lights in series, and they are in series with 2 lights in parallel. If the 13 lights are identical, which of them w

ill burn brightest?
11 lights
2 lights
all 13 lights
none will be brightest
Physics
1 answer:
BlackZzzverrR [31]3 years ago
8 0
<h2>Answer: 2 lights (in parallel)</h2>

Explanation:

When light bulbs are connected in series the total voltage V_{s} will be:

V_{s}=V_{1}+V_{2}+...+V_{n}  (1)

This means the <u>total voltage will be distributed among each of the bulbs</u> in series, therefore the luminosity will be also divided among the bulbs.

When lights are connected in parallel the total voltage V_{p} will be:

V_{p}=V_{1}=V_{2}=...=V_{n}  (2)

This means the <u>total voltage will be the same for each bulbs</u> in parallel, therefore the luminosity will be the same.

Now, if we combine this two types of connections, as in this problem with 11 lights in series, which are also in series with 2 lights in parallel; the 2 lights in parallel will be brighter than the 11 lights in series.

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A yo‑yo with a mass of 0.0800 kg and a rolling radius of =2.70 cm rolls down a string with a linear acceleration of 5.70 m/s2.
N76 [4]

Explanation:

Given that,

Mass, m = 0.08 kg

Radius of the path, r = 2.7 cm = 0.027 m

The linear acceleration of a yo-yo, a = 5.7 m/s²

We need to find the tension magnitude in the string and the angular acceleration magnitude of the yo‑yo.

(a) Tension :

The net force acting on the string is :

ma=mg-T

T=m(g-a)

Putting all the values,

T = 0.08(9.8-5.7)

= 0.328 N

(b) Angular acceleration,

The relation between the angular and linear acceleration is given by :

\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{5.7}{0.027}\\\\=211.12\ m/s^2

(c) Moment of inertia :

The net torque acting on it is, \tau=I\alpha, I is the moment of inertia

Also, \tau=Fr

So,

I\alpha =Fr\\\\I=\dfrac{Fr}{\alpha }\\\\I=\dfrac{0.328\times 0.027}{211.12}\\\\=4.19\times 10^{-5}\ kg-m^2

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3 years ago
Miles is camping in Glacier National Park. In the midst of a glacier canyon,
valentina_108 [34]

Answer:

t=1.623 sec

Explanation:

The distance traveled before the echo is had is:

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Given the speed of sound as v=345m/s, we use the speed equation to solve for t:

v=\frac{d}{t}\\\\345\ m/s=\frac{560m}{t}\\\\t=\frac{560}{360}\\\\=1.623 \ s

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2 years ago
When the displacement in SHM is equal to 1/3 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b
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Answer:

Explanation:

Given

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U=\frac{1}{2}kx^2

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T.E.=\frac{1}{2}kA^2

Total Energy=kinetic Energy+Potential Energy

K.E.=\frac{1}{2}kA^2 -\frac{1}{18}kA^2

K.E.=\frac{8}{18}kA^2

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2 years ago
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