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Flauer [41]
3 years ago
11

A buffer is prepared containing 0.75 M NH3 and 0.20 M NH4 . Calculate the pH of the buffer using the Kb for NH3. g

Chemistry
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

pH=8.676

Explanation:

Given:

0.75 M NH_{3}

0.20 M NH_{4}

The objective is to calculate the pH of the buffer using the kb for NH_3

Formula used:

pOH=pka+log\frac{[salt]}{[base]}\\

pH=14-pOH

Solution:

On substituting salt=0.75 and base=0.20 in the formula

pOH=-log(1.77*10^{-5})+log\frac{0.75}{0.20}\\        =4.75+0.5740\\        =5.324

pH=14-pOH

On substituting the pOH value in the above expression,

pH=14-5.324

Therefore,

pH=8.676

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