Ask question

Ask question

All categories

sertanlavr [38]

4 years ago

11

The standard molar heat of vaporization for water is 40.79 kj/mol. How much energy would be required to vaporize 4.72 x 10^10 mo

lecules of water

1 answer:

stellarik [79]4 years ago

7 0

(5.81 x 10^10 molecules) / (6.022 x 10^23 molecules/mol) x (40.79 kj/mol) = 3.94 x 10^-12 kj

You might be interested in

prove that the rate of heat production in each of the two resistors connected in parallel are inversely proportional to the resi

Katyanochek1 [597]

I believe that the answer to the question provided above is that with increase in resistance provided with constant current, Power dissipated will be lessen since power loss is high. Low power dissipation has low heat production.
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

5 0

3 years ago

Why do we not consider the strong nuclear force when we describe the forces between atoms?

solong [7]

This is because, nuclear forces are short range forces.

The protons and neutrons are collectively called nucleons and they are found in the nucleus of an atom. These nucleons are held together by a strong attractive force called the nuclear force.

When atoms combine, they are held together by forces determined by electrons in the outermost shell. The influence of the nuclear force does not extend beyond the nucleus because they are short range forces.

Hence, we not consider the strong nuclear force when we describe the forces between atoms.

Learn more:brainly.com/question/3964366

3 0

3 years ago

a runner covers the last straight stretch of the race in 4 s. durning that time, he speeds up from 5 m/s to 9m/s what is the run

Sergio039 [100]

Answer:

The runner's acceleration was $1\ m/s^2$

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

$v_f=v_o+at$

Solving for a:

$\displaystyle a=\frac{v_f-v_o}{t}$

The runner speeds up from vo=5 m/s to vf=9 m/s in t=4 seconds, thus:

$\displaystyle a=\frac{9-5}{4}$

$\displaystyle a=\frac{4}{4}=1$

The runner's acceleration was $1\ m/s^2$

5 0

3 years ago

A plane travels 1743 KM in 2 hours 30 minutes. How fast was the plane traveling?

Advocard [28]

Answer:

$v=697.2km/h$

Explanation:

Hello.

In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

$V=\frac{d}{t}$

The distance is clearly 1743 km and the time is:

$t=2h+30min*\frac{1h}{60min} =2.5h$

Thus, the velocity turns out:

$v=\frac{1743km}{2.5h}\\ \\v=697.2km/h$

Which is a typical velocity for a plane to allow it be stable when flying.

Best regards.

5 0

3 years ago

A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains

Vikki [24]

Hey i dont have an answer but i need the points for finals today. Thank you

6 0

3 years ago

Read 2 more answers