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stellarik [79]
4 years ago
9

The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume e =

1 for these surfaces. Find the radii of the following stars (assumed to be spherical):________
(a) Rigel, the bright blue star in the constellation Orion, which radiates energy at a rate of 2.7×1032W and has surface temperature 11,000 K;
(b) Procyon B (visible only using a telescope), which radiates energy at a rate of 2.1×1023W and has surface temperature 10,000 K.
(c) Compare your answers to the radius of the earth, the radius of the sun, and the distance between the earth and the sun. (Rigel is an example of a supergiant star, and Procyon B is an example of a white dwarf star.)
Physics
1 answer:
Svetllana [295]4 years ago
7 0

Answer:

Explanation:

(a) Rigel, 2.7x10^32W, T = 11,000K

But L = 4pR²sT⁴

L = 2.7x10^32W, T = 11,000K, s= 5.67 x 10^-8, R= radius in meters

Rigel parallax, p = 0.00378 arc sec

Substituting the various values and making R the subject of the formula

R² = L/(4psT⁴)

R² = 2.7x10^32/(4 x 0.003878 x 5.67x10^-8 x (11,000)⁴)

R² = 2.7x10^32/1.2877x10^7

R² = 2.096761668 x 10^25

R = 4.579041021 x 10^12meters

(b)

Procyon B, 2.1x10^23W, T = 10,000K

But L = 4pR²sT⁴

L = 2.1x10^23W, T = 10,000K, s= 5.67 x 10^-8, R= radius in meters

Procyon B parallax, p = 0.00284 arc sec

R² = 2.1x10^23/(4 x 0.00284 x 5.67x10^-8 x (10,000)⁴)

R² = 2.1x10^23/(6.441 x 10^6)

R² = 3.26036 x 10^16

R = 1.80565 x 10^8 meters

(c) The radius of Rigel is given as 4.579041021 x 10^12meters and the radius of Procyon B is given by 1.80565 x 10^8 meters shows the remarkable difference between a super-giant star(Rigel) and a white dwarf star (Procyon B)

The radius of the sun a red star is 6.96 x 10^8meters which shows a certain level of resemblance with the size of a dwarf white star Procyon B.

The sun is larger than Procyon B as estimated above.

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What is the power of a machine that transfers 15,000J of energy in 1 minute?
____ [38]

Answer:

answer is 250 W

Explanation:

W=P * t

t=60s

W= 15000J

15000= P * 60

P= 15000/60

P= 250W. (SI unit of power Watt)

5 0
3 years ago
A superball with a mass m = 61.6 g is dropped from a height h = [02]____________________ m. It hits the floor and then rebounds
aleksklad [387]

<em>There is not enough data to solve the problem, but I'm assuming the initial height as h = 10 m for the question to have a valid answer and the student can have a reference to solve their own problem</em>

Answer:

(a) \Delta P=1.67 \ kg.m/s

(b) \Delta P=0.86\ m/s

Explanation:

<u>Change of Momentum</u>

The momentum of a given particle of mass m traveling at a speed v is given by

P=m.v

When this particle changes its speed to a value v', the new momentum is

P'=m.v'

The change of momentum is

\Delta P=m.v'-m.v

\Delta P=m.(v'-v)

Defining upward as the positive direction, we'll compute the change of momentum in two separate cases.

(a) The initial height of the superball of m=61.6 gr = 0.0616 Kg is set to h= 10 m. This information leads us to have the initial potential energy of the ball just after it's dropped to the floor:

U=m.g.h=0.0616\cdot 9.8\cdot 10 =6.0368\ J

This potential energy is transformed into kinetic energy just before the collision occurs, thus

\displaystyle \frac{1}{2}mv^2=6.0368

Solving for v

\displaystyle v=\sqrt{\frac{6.0368\cdot 2}{0.0616}}

v=-14\ m/s

This is the speed of the ball just before the collision with the floor. It's negative because it goes downward. Now we'll compute the speed it has after the collision. We'll use the new height and proceed similarly as above. The new height is

h'=88.5\% (10)=8.85\ m

The potential energy reached by the ball at its rebound is

U'=m.g.h'=0.0616\cdot 9.8\cdot 8.85 =5.342568\ J

Thus the speed after the collision is

\displaystyle v'=\sqrt{\frac{5.342568\cdot 2}{0.0616}}

v'=13.17\ m/s

The change of momentum is

\Delta P=0.0616\cdot (13.17+14)

\Delta P=1.67 \ kg.m/s

(b) If the putty sticks to the floor, then v'=0

\Delta P=0.0616\cdot (0+14)

\Delta P=0.86\ m/s

3 0
4 years ago
The planet Jupiter orbits the Sun at a nearly constant speed. Which of the following statements are true?
RoseWind [281]

Answer:

a. There is a force on Jupiter toward the center of the orbit.

d. Jupiter is accelerating toward the center of the orbit.

Explanation:

Let us look at each of the choices one by one:

a. There is a force on Jupiter toward the center of the orbit.

True. The sun being at the center of Jupiter's orbit, pulls the planet towards it (providing the centripetal force), therefore, there exists a force on Jupiter toward the center of the orbit.

b. There is a force on Jupiter pulling it out from the center of the orbit.

Nope. The centripetal force due to gravity acts towards the center of the orbit.  

c. There is a force on Jupiter in the direction of its motion.

Nope. There exists only the centripetal force acting towards the center of the orbit,

d. Jupiter is accelerating toward the center of the orbit.

Yes. Because of the centripetal force gravity provides, Jupiter is accelerating towards the center of the orbit, but it does not fall in because it has velocity perpendicular to the direction of its acceleration.

6 0
3 years ago
The battery charger for an mp3 player contains a step-down transformer with a turns ratio of 1:38, so that the voltage of 120 v
matrenka [14]
Transformer contains two coils: primary and secondary. They allow change of voltage to lower or higher value. In first case we have step-down and in second case we have step-up transformer.
Formula used for transformer is:\frac{N_{1} }{N_{2}} = \frac{V_{1}}{V_{2}}

Where:N1 = number of turns on primary coilN2 = number of turns on secondary coilV1 = voltage on primary coilV2 = voltage on secondary coil
In a step-down transformer primary coil has more turns than secondary coil. So the ratio 1:38 means that for each turn on secondary coil we have 38 turns on primary coil.
We can solve the equation for V2:V_{2} =  \frac{ V_{1}* N_{2}  }{ N_{1} }  \\  V_{2} =  \frac{ 120* x  }{ 38x} } \\ V_{2} = 3.16V

Secondary coil provides voltage of 3.16V.
7 0
4 years ago
PLEASE HELP ME WITH THIS
Kitty [74]

Answer:

i think it might be c but i know its not A or B and im

on the fence for D so the best answer would be C

Explanation:

3 0
3 years ago
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