The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
U = m ΔT
U = Energy
= Specific heat
m = Mass
ΔT = Change in temperature
ρ = Density
V = Volume
ρ = 1000 g / m³ (Dry air )
= 1 J / g K
ΔT = 5 °C
V = 4 * 4 * 3
V = 48 m³
m = ρ V
m = 1000 * 48
m = 48000 g
U = 1 * 48000 * 7
U = 336000 J
U = 336 kJ
Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
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Answer:
a) 0 J
b) 0.92J
Explanation:
The work is defined as:
because the normal force is perpendicular to the displacement the work done for it is zero.
The force because of frictions has an angle of 180 degrees because it is opposite to the motion, so:
Answer:
<em>I</em><em> </em><em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>. </em>
Explanation:
Vs/Vp = Ns/Np
Vs/9 = 30/300
Vs/9 = 1/10
Vs= 9/10 = 0.9 volts
It is a Step down transformer. This is because the number of turns on the primary coil is greater than that on the secondary coil.
Answer:
Explanation:
First, it is required to model the function that models the increasing force in the +x direction:
The equation is:
The impulse done by the engine is given by the following integral: