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2 years ago

Indicate whether each of the following would increase or decrease the rate of reaction

Chemistry

1 answer:

mote1985 [20]2 years ago

7 0

The rate of a chemical reaction is affected by temperature, Catalysts, Suface area, Concentration.

<h3>Rate of reaction</h3>

The rate of a chemical reaction is the rate at which the concentration of reactant molecules decreases or the concentration of product molecules increases.

<h3>Factors effecting rate of chemical reaction </h3>

The factors that affect the rate of chemical reaction include:

Temperature: increase in temperature increases reaction rate while decrease in temperature decreases reaction rate.
Catalysts: the present of catalysts increase the reaction rate. Some catalysts decreases reaction rate and are known as negative catalysts.
Surface area: increase in surface area of reactants increases reaction rate.
Concentration: Increase in concentration of reactants increases reaction rate while decrease in concentration of reactants decreases reaction rate.

Therefore, the rate of a chemical reaction is affected by temperature, Catalysts, Suface area, Concentration.

Learn more about rate of reaction and factors affecting reaction rate at: brainly.com/question/15841605

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The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

7 0

2 years ago

A block is found to have volume of 35.3 cm3. It’s mass is 31.7g. Calculate the density of the block

11111nata11111 [884]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{35.3}{31.7} \\ = 1.113564$

We have the final answer as

Hope this helps you

6 0

2 years ago

what is the chemical reaction in which the exchange of electropositive and electronegative ions occurs in aqueous solution

defon

Answer:

chemical reaction are the processes in which new substances with new properties of from are called as chemical reaction ex double displacement reaction

Explanation:

7 0

2 years ago

Read 2 more answers

. The freezing point of an aqueous solution containing a nonelectrolyte solute is – 2.79 °C. What is the boiling point of this s

Semmy [17]

Answer:

Boiling point of the solution is 100.78°C

Explanation:

This is about colligative properties.

First of all, we need to calculate molality from the freezing point depression.

ΔT = Kf . m . i

As the solute is nonelectrolyte, i = 1

0°C - (-2.79°C) = 1.86 °C/m . m . 1

2.79°C / 1.86 m/°C = 1.5 m

Now, we go to the boiling point elevation

ΔT = Kb . m . i

Final T° - 100°C = 0.52 °C/m . 1.5m . 1

Final T° = 0.52 °C/m . 1.5m . 1 + 100°C → 100.78°C

4 0

3 years ago

Which side does the light always start from?

jarptica [38.1K]

Answer:

in prism

it's from the rectangular reflecting surface

7 0

2 years ago