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Ivahew [28]
3 years ago
14

Calculate the root mean square velocity of nitrogen molecules at 25°c.

Physics
1 answer:
umka2103 [35]3 years ago
5 0

Answer:

515.22 m/s

Explanation:

Formula for root mean square velocity is SQRT (3RT/M)

Where,

R = Rydberg's constant = 8.314 Kg. m²/ s². K. mol

T = Temperature in Kelvin

M = Molar mass in Kg/mol

First calculate molar mass,

As nitrogen is diatomic molecule,

Its molar mass is

M = 2(14) = 28 g/mol

Convert unit into Kg/mol

28 g/mol x 1 Kg/1000g = 2.8x10¯² Kg/mol

Convert temperature into kelvin

T = 25 + 273 = 298K

Put all values in formula

Vrms = SQRT (3RT/M)

Vrms = SQRT (3x8.314x298/2.8x10¯²)

Vrms = SQRT (265454. 14)

Vrms = 515.22 m/s

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C
AlexFokin [52]

Answer:

27J  

3528J

Explanation:

First problem:

Given parameters:

Mass of tennis ball  = 0.06kg

Velocity of tennis ball  = 30m/s

Unknown:

Kinetic energy  = ?

Solution:

Kinetic energy is the energy due to the motion of a body.

It is expressed as:

       K.E  = \frac{1}{2} m v²  

       K.E =  \frac{1}{2}  x 0.06 x 30²   = 27J  

Second problem:

Given parameters:

Mass = 30kg

Height  = 12m

Unknown:

Potential energy  = ?

Solution:

Potential energy is the energy due to the position of a body.

  Mathematically;

       Potential energy  = mgh

m is the mass

g is the acceleration due to gravity

h is the height

 Now;

          Potential energy  = 30 x 9.8 x 12  = 3528J

7 0
3 years ago
From the anatomical position, the digits are ____ to the brachium.
PIT_PIT [208]
A I believe if not I’m sorry
4 0
3 years ago
Read 2 more answers
An object with 274 J of GPE is 140cm above the ground. What is its mass?
Amanda [17]
E=274J
h=140cm=1,4m
g≈9,8m/s²

m=?

E=mgh
m=E/gh=274J/9,8m/s²*1,4m≈20kg



"Non nobis Domine, non nobis, sed Nomini tuo da gloriam."



Regards M.Y.
3 0
3 years ago
A substance that is made of atoms of more than one type bound together is called a
BigorU [14]
The substance that is made of atoms of more than one type bound together is called an atomic bond or a multi bond
6 0
3 years ago
What is the magnitude of the magnetic dipole moment of the bar magnet
Annette [7]

The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²

<h3> Magnetic dipole moment of the bar magnet</h3>

The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}

where;

  • B is magnetic field
  • m is dipole moment
  • μ is permeability of free space

m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)

m = 1.2 Am²

The complete question is below:

What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.

Learn more about dipole moment here: brainly.com/question/27590192

#SPJ11

6 0
2 years ago
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