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Alchen [17]
3 years ago
15

an engine has been design to work between source and the sink at temperature 177 degree Celsius and 27 degree Celsius respective

ly. if the energy input is 3600 joule. what is the work done by the engine
Physics
1 answer:
irina [24]3 years ago
4 0

<u>Given data</u>

Source temperature (T₁) = 177°C = 177+273 = 450 K

Sink temperature (T₂) = 27°C = 27+273 = 300 K

Energy input (Q₁) = 3600 J ,

Work done = ?

                We know that, efficiency (η) = Net work done ÷ Heat supplied

                                                           η =   W ÷ Q₁  

                                                           W = η × Q₁

               First determine the efficiency ( η ) = ?

                                Also, we know that ( η ) = (T₁ - T₂) ÷ (T₁)

                                                                        = 33.3% = 0.333

               Now, Work done is W = η × Q₁

                                                    = 0.33 × 3600

                                                 <em>  W = 1188 J</em>

<em>Work done by the engine is 1188 J</em>

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A woman on a bridge 95.6 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an a
NARA [144]

Answer:

The speed of the raft is 1.05 m/s

Explanation:

The equation for the position of the stone is as follows:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the stone at time t

y0 = initial height

v0 = initial speed

t = time

g = acceleration due to gravity

The equation for the position of the raft is as follows:

x = x0 + v · t

Where:

x = position of the raft at time t

x0 = initial position

v = velocity

t = time

To find the speed of the raft, we have to know how much time the raft traveled until the stone reached the river. For that, we can calculate the time of free fall of the stone:

y = y0 + v0 · t + 1/2 · g · t²      (v0=0 because the stone is dropped from rest)

If we place the origin of the frame of reference at the river below the bridge:

0 m = 95.6 m - 9.8 m/s² · t²

-95.6 m / -9,8 m/s² = t²

t = 3.12 s

We know that the raft traveled (4.84 m - 1.56 m) 3.28 m in that time, then the velocity of the raft will be:

x/t = v

3.28 m / 3.12 s = v

v = 1.05 m/s

5 0
3 years ago
Read 2 more answers
What is the best description of temperature?
Nonamiya [84]

Explanation:

o has Celsius of indirect measurment

5 0
3 years ago
4 Four objects are stiuated along the y axis as follow: a 20 kg object is at +3 m, a 3 kg object is at +2.5 m, a 2.5 kg object i
FinnZ [79.3K]

Answer: 1.348 meters

Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point  c . Adding the four moments together, we get:

(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0

6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0

11.5c=15.50

c=  1.348 metres

The center of mass is on the y axis at  y  = 1.348 metres.

4 0
1 year ago
it takes 29.5 minutes to walk with an average velocity of 1.2 m/s to the north from the bus stop to the museum entrance what is
olasank [31]

Displacement is distance moved,so if you have your velocity in m/s you need your total time in seconds and multiply the two to get displacement so at 1.2m/s travelling (9.5*60(60seconds in a minute)=570 seconds is 570*1.2=684

8 0
3 years ago
In 1996, NASA performed an experiment called the Tethered Satellite experiment. In this experiment a 3.42 x 104-m length of wire
makvit [3.9K]

Answer:

15116.4 V

Explanation:

B = Earth's magnetic field at the location = 6.5\times 10^{-5}\ T

L = Length of the wire = 3.42\times 10^4\ m

v = Velocity of the shuttle = 6.8\times 10^8\ m/s

The emf generated is given by

E=BLv\\\Rightarrow E=6.5\times 10^{-5}\times 3.42\times 10^{4}\times 6.8\times 10^3\\\Rightarrow E=15116.4\ V

The motional emf generated between the ends of the wire is 15116.4 V

8 0
3 years ago
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